Can You Simplify Integrals by Separating Radicals?

Cacophony
Messages
41
Reaction score
0

Homework Statement


for the following integrals, am I allowed to break them up like so:

1. ∫(1)/(sqrt(16-9x²)³) dx

= ∫(1)/(√16)³ · ∫(1)/(√-9x²)³ dx

2. ∫(x²)/(sqrt(x²-9)) dx

= ∫(x²)/(√x²) · ∫(x²)/(√-9) dx

3. ∫(1)/(x²(sqrt(a²+x²))) dx

= ∫(1)/(x²) · ∫(1)/(√a²) · ∫(1)/(√x²) dx

? ? ?


Homework Equations


none


The Attempt at a Solution


I need to know if I'm allowed to break them up like this before I start attempting a solution
 
Physics news on Phys.org
Is this what you are writing for #1?
\int \frac{1}{\left( \sqrt{16-9x^2}\right)^3} dx
=\int \frac{1}{\left( \sqrt{16}\right)^3} dx \cdot \int \frac{1}{\left( \sqrt{-9x^2}\right)^3} dx
Yikes. No, you cannot do that!

\sqrt{a - b} \ne \sqrt{a} \cdot \sqrt{-b}
Better review the properties of radicals.
 
Ok, guess i'll try something else. Thanks
 
Thread 'Use greedy vertex coloring algorithm to prove the upper bound of χ'
Hi! I am struggling with the exercise I mentioned under "Homework statement". The exercise is about a specific "greedy vertex coloring algorithm". One definition (which matches what my book uses) can be found here: https://people.cs.uchicago.edu/~laci/HANDOUTS/greedycoloring.pdf Here is also a screenshot of the relevant parts of the linked PDF, i.e. the def. of the algorithm: Sadly I don't have much to show as far as a solution attempt goes, as I am stuck on how to proceed. I thought...

Similar threads

Back
Top