Car accelerated by repulsion of two point charges

AI Thread Summary
The discussion revolves around a theoretical problem involving two point charges of like polarity repelling each other, with one charge attached to a car. The challenge is to derive a function for the car's speed over time, given the forces involved and the mass of the car. The initial approach using energy conservation leads to a final speed calculation, but participants note the difficulty in expressing the distance as a function of time. Suggestions include using energy conservation principles and considering the application of Laplace transforms to solve the problem. The conversation highlights the complexities of integrating the variable distance in the context of the car's acceleration.
wackyvorlon
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At the outset, I want to explain that this is a problem I came up with myself. It's not actually homework, and I suspect it is deeply conceptually flawed in some manner that I have yet to determine.

1. Two point charges of like polarity, ## q_1 = q_2 = 1C ##, start out separated by distance ## x = 1m ##. ##q_2## is attached to a car of mass ##m=1000kg##. When released, the car is accelerated by the force repelling the two charges. Find a function ## v(t) ## which gives the speed at time t.

Homework Equations



$$ F = k \frac{q_1 q_2}{x^2} $$

$$ a = \frac{F}{m} $$

$$ v = a t $$

Potential Energy

$$ U = k \frac{q_1 q_2}{x} $$

Kinetic Energy

$$ K = \frac{1}{2} m v^2 $$

The Attempt at a Solution



This has been giving me fits. I keep ending up in circular definitions. Firstly, I approach from the perspective of energy, ## U_0 = K_f ##. The end result of that was that the final speed should be ## 3.16*10^3 \frac{m}{s} ##.

## F ## becomes: $$ F = \frac{k}{x^2} $$

Inserting into Newton's second law I get:

$$ a = \frac{k}{m x^2} $$Then:

$$ v = \frac{k}{m x^2} t $$

You'll notice my problem. Through some means, I have to express ## x ## in terms of ## t ##, but every idea I've had relies, ultimately, on ## x ##. Truthfully, to list the approaches I've tried in detail here would require quite some typing. I feel intuitively that there ought to be some way to solve this, but frankly I'm at a loss. Any assistance you can provide in pointing me in the right direction would be greatly appreciated.
 
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wackyvorlon said:
a=k/mx2
Ok.
wackyvorlon said:
v=(k/mx2)t
Not ok.
x is a variable. You cannot integrate x-2 by simply multiplying by t.

You can use energy conservation to find the velocity as a function of position, but getting it as a function of time is quite tricky.
 
Thanks! Your help is greatly appreciated.

I've been wondering if perhaps this would be a good application of the laplace transform?
 
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