- #36
Ilja
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Yes, but if you start with SR field theory, you start with [itex]R^4[/itex].stevendaryl said:But it seems to me that the topology of the universe is a separate assumption. You can do field theory on top of [itex]R \times S^3[/itex] (or whatever) just as well as on top of [itex]R^4[/itex].
You may ask why the spin 2 iteration approach to obtain the Einstein equations has to start with spin 2 on Minkowski background instead of a spherical one. Hm, I don't know. In the case of the ether interpretation, the situation is different, the harmonic coordinates used there are simply simpler, thus, Occam's razor works. Maybe this can be extended to spin 2 theory on [itex]R \times S^3[/itex] too. Last but not least, a local approximation of an [itex]R \times S^3[/itex] theory would be on [itex]R^4[/itex], and approximations are usually simpler.
That's really hard. Test bodies which cover every single point - because one point of space would be sufficient to S3 X R to [itex]R^4[/itex].PAllen said:Let's say a bunch of test bodies are sent 'around the closed universe'. If one of is unable to return, you've falsified that the topology is really S3 X R.
And, by the way, why would the ether interpretation predict something different? It is the same equation, the same solution, and the part where above solutions agree covers the whole history of the observer. The argument remains intact.