Centre of Pressure: Explained and Examined

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The discussion explores the concept of the center of pressure, comparing it to mathematical representations of curl, suggesting that both condense complex distributions to a single point. It clarifies that in aviation, changing the center of pressure with air-brakes alters pressure distribution and increases drag, which can enhance airflow stability at high speeds. The conversation also touches on the mathematical representation of curl, noting that mathematicians use the curl operator to express rotational effects in vector fields. Additionally, it explains the relationship between gradient, curl, and divergence in vector calculus. Overall, the center of pressure is crucial in understanding aerodynamic forces on aircraft.
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Is centre of pressure the same way they represent curl in mathematics ? i.e representation of pressure condensed to a single point?

Also,on a tv show,the presenter said this about the air-brakes on a P-28 fighter,"The air-brakes change the centre of pressure thereby allowing the wind-flow to stick at high speeds".What does he mean by this?
ASIDE:Since I guess the representation of centre of pressure is pretty similar to curl,could someone please tell me why mathematicians use the gradient to represent curl?

As a engineer,I'm more used to seeing exercises where curl is calculated using the position vector 'dr' and then taking the line integrals.How can I prove that the gradient x field=line integral stuff ?
Thanks.
 
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Center of pressure is like a center of mass. In aircraft it is kinda where the wing's lift appears to be acting.
http://www.grc.nasa.gov/WWW/k-12/airplane/cp.html

The description in the documentary sounds like garbled rubbish to me. Clearly the air-brake changes the pressure distribution dramatically giving you a lot of drag which could be described as making the air stick ...

AFAIK. mathematicians represent curl as, well, curl. You mean \text{curl}(\vec{V}) = \vec{\nabla} \times \vec{V}? This is the differential form of the integral equations you are used to - they are easier to use in general. Multiply it out and see what happens.

Gradient is like this: \text{grad}V=\nabla V and the other one is the divergence: \text{div}(\vec{V}) = \vec{nabla}\cdot\vec{V}
 
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