Characteristic X-Ray Kα & Kβ Line Energies

AI Thread Summary
The discussion focuses on calculating the energies of the characteristic Kα and Kβ X-ray lines using the formula E = (energy level)(Z-1)²/n². Participants clarify that the Kα line results from electron transitions from the L-shell (n=2) to the K-shell (n=1), while the Kβ line involves transitions from the M-shell (n=3) to the K-shell. Confusion arises regarding which energy levels to use, particularly whether to apply the K-shell or L-shell energy for calculations. Ultimately, it is confirmed that Kα radiation is emitted when transitioning from E2 = -11.3 keV to E1 = -69.5 keV. The conversation concludes with participants expressing gratitude for the clarification on the procedure.
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Homework Statement


What are the energies of the characteristic Kα line and Kβ lines?

Homework Equations


K-shell ( n =1):-69.5 keV
L-shell ( n =2 ): -11.3 keV
M-shell ( n =3 ): -2.30 keV
Z = 74
E = (energy level) (Z-1)2/n2

The Attempt at a Solution


for alpha i have
(-11.3keV) (74-1)2/22 for n =2

i know to find the energy characteristic i need to go from n=1 to n=2. so i know E = E1-E2
but for n=1 do use the energy level of the Kshell or the energy level of the Lshell?
in the lecture notes the instructed used the same energy level but didnt specify which one.
 
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The emmission occur when the electron transits from a higher energy level to a lower energy level,
eg E2 -E1
The Kα line is produced by transitions from the L to the K shell and the Kβ for transitions
from the M to the K shell - see HyperPhysics X-ray transitions.
 
Ok thank you. So it's E2-E1? My instructor did it the other way.

But I still don't know which energy level to use. Like I said my instructor used the same energy level twice. She didn't specify if it was the Kshell or the Lshell.
 
The picture Andrevs link is clear enough !
Kα radiation is emitted when the energy of the electron goes down from E2 = -11.3 keV to E1 = -69.5 keV
 
ok i get it guys. i was misinterpreting the question as well as the procedure to solve it.
 
thank you!
 
You're welcome.
 
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