Chebyshev's theorem (statistics)

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Chebyshev's theorem can be applied to predict the number of students within plus and minus 2 standard deviations from the mean in a quiz taken by 100 students. The formula 1 - 1/k^2 indicates that for k=2, the proportion of students expected within this range is at least 75%. This means that at least 75 students are predicted to score within this interval. It's important to note that this percentage represents a lower bound, not an exact figure. Understanding the theorem's implications is crucial for accurately interpreting the results.
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Homework Statement


If 100 students take a quiz, use chebyshev's theorem to predict the number of students plus and minus 2 standard deviations from the mean.

Homework Equations


1-1/k^2 where k is standard deviations

The Attempt at a Solution


I think its 75, but I'm not sure...I'm just trying to get this concept down
 
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staples82 said:

Homework Statement


If 100 students take a quiz, use chebyshev's theorem to predict the number of students plus and minus 2 standard deviations from the mean.

Homework Equations


1-1/k^2 where k is standard deviations
Don't just memorize formulas, learn what they say! Did you notice that "1- 1/k2" is not even an equation? What is equal to 1- 1/k2?

The Attempt at a Solution


I think its 75, but I'm not sure...I'm just trying to get this concept down
1- 1/22= 1- 1/4= 3/4. 3/4 of 100= 75. Now, if "the fraction of trials within k standard deviations of the mean" is what 1- 1/k2 gives, you are completely correct!
 
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Chebyshev's Theorem does indeed state give the percentage data you can expect to find within \pm k standard deviations of the mean, as long as k > 1 (and it is here.
However, remember that technically the answer is a lower bound, so you the proper response not that the percentage is 75\%, but that it is at least 75\%.
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.

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