CIRCUIT ANALYSIS: 2 resistors, Indep. Current Source, V.C.C.S - find v0

In summary: But doesn't that change the calculation of v\,=\,i\,R?v\,=\,i\,R\,=\,(-1.429\,A)\,(10\Omega)\,=\,-14.3\,VVS.v\,=\,i\,R\,=\,(-11.43\,A)\,(10\Omega)\,=\,-114.3\,VI'm thoroughly...thoroughly confused. :(hmmmm, let me see. The i = -1.429A is the current through 10ohm. So the voltage is -14.29V through both resistors. The voltage
  • #36
the problem is you set V6 = V of the V.C.C.S. remember it's both resistors combined

I updated that diagram to hopefully make it more obvious
 
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  • #37
[tex]V_{V.C.C.S.}\,=\,V_{6\Omega}\,+\,V_{4\Omega}\,=\,(-8.57\,V)\,+\,(-5.71\,V)\,=\,-14.28\,V[/tex]

[tex]P_{V.C.C.S.}\,=\,V_{V.C.C.S.}\,I_{V.C.C.S.}\,=\,(-14.28\,V)\,(-11.43\,A)\,=\,163.2\,W[/tex]

Finally!
 
  • #38
Good job. Practice with these circuits and you'll be able to do them in your sleep in no time
 

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