Classical mechanics - finding distance D in terms of velocity

AI Thread Summary
The discussion focuses on solving a physics problem involving a skydiver experiencing linear air resistance. The equations of motion are established, with the total force equating to the mass times acceleration, incorporating both gravitational and air resistance forces. The "vdv/dx trick" is utilized to eliminate time from the equations, leading to a relationship between distance and velocity. Participants suggest simplifying the equation by eliminating mass and separating variables to isolate velocity and distance. The next step involves integrating the equation, with participants clarifying the limits based on the initial conditions of the problem.
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Homework Statement



"A passenger (mass m) initially at rest steps out of an airplane. Assume down is the positive x-axis and put the origin at the airplane. Assume the air resistance force is linear in the velocity so F(air)= -mbv. Find the distance D he has fallen when his velocity is v."

Homework Equations



Equations of motion

The "vdv/dx trick": d2z/dt2 = (z-dot)*(d(z-dot)/dz)

F(tot) = ma

F(air) = -mbv

Weight = mg

The Attempt at a Solution



Here's how far I've gotten:

Since the skydiver is only falling in the x direction, there's only one equation of motion, which I found to be ma = -mbv + mg [or, alternatively, m(x-double dot) = -mb(x-dot) + mg]. Now, I know I want the relation of distance and velocity, without time, so I use the "vdv/dx" trick (so that there's no longer time in the equation).

That makes this mv*(dv/dx) = -mbv + mg, or m(x-dot)*(d(x-dot)/dx) = -mb(x-dot) + mg. I rearranged this to get dx = (-m/b)*(vdx/v-(mg/b)), where -(mg/b) is the terminal velocity.
I'm sorry for all the writing, but am I correct so far? And how do I continue to solve the problem from here? Any help would be appreciated.
 
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First off, divide through by m to simplify the expression a bit. Secondly, can you separate variables, i.e have things with "v" on one side and "x" on the other?
 
First, since m is common to every term, I would eliminate that to make things easier. Next, you have vdv/dx = g-bv. Try to isolate v and dv on one side, and dx on the other side.
 
Alright, so...

I went back and simplified what I had first and ended up with v(dv/dx) = -bv - g. So, after isolating dz, I end up with dz = -(vdv/(bv+g)).

Now, I know my next step is to integrate this, but I'm not sure what the limits would be.
 
The problem tells you what the limits should be.

"A passenger (mass m) initially at rest steps out of an airplane. Assume down is the positive x-axis and put the origin at the airplane. Assume the air resistance force is linear in the velocity so F(air)= -mbv. Find the distance D he has fallen when his velocity is v."
 
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