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- TL;DR Summary
- How does a coil spring react to a low amplitude pulse applied to one end?
I am trying to understand the reaction of a steel coil compression spring when pulsed. The spring I am interested in has the following physical characteristics:
k (spring constant in pounds per inch) = 2.88
d (wire diameter in inches) = .043
n (number of active coils) = 29
D (mean diameter of the coil in inches) = .430
Lf (spring free length is inches) = 6.55The spring is mounted to a fixed plate on one end and a moveable plate on the other. The spring is at rest. It is compressed to a length of 3.75" and held there by the moveable plate. In this condition, the spring is exerting a force of about 8.064 pounds on the plates. If it matters, the moveable plate weighs 19 ounces.The moveable plate is subjected to a pulse that accelerates the plate at a rate of 29,400 ft/sec^2 for a period of .8 milliseconds (by a force of about 1,091 pounds applied to the moveable plate).
Intuitively, it seems to me that the spring will not have time to react to the pulse, so the presence of the spring has no practical effect on the acceleration of the moveable plate. However, I actually have no idea how to determine the length of time it would take the pulse to propagate the length of the spring.
I will appreciate any and all responses. Just to be clear, I am not looking for a lengthy explanation here. I would like to be pointed in the right direction and a link to some of that information would be greatly appreciated.
k (spring constant in pounds per inch) = 2.88
d (wire diameter in inches) = .043
n (number of active coils) = 29
D (mean diameter of the coil in inches) = .430
Lf (spring free length is inches) = 6.55The spring is mounted to a fixed plate on one end and a moveable plate on the other. The spring is at rest. It is compressed to a length of 3.75" and held there by the moveable plate. In this condition, the spring is exerting a force of about 8.064 pounds on the plates. If it matters, the moveable plate weighs 19 ounces.The moveable plate is subjected to a pulse that accelerates the plate at a rate of 29,400 ft/sec^2 for a period of .8 milliseconds (by a force of about 1,091 pounds applied to the moveable plate).
Intuitively, it seems to me that the spring will not have time to react to the pulse, so the presence of the spring has no practical effect on the acceleration of the moveable plate. However, I actually have no idea how to determine the length of time it would take the pulse to propagate the length of the spring.
I will appreciate any and all responses. Just to be clear, I am not looking for a lengthy explanation here. I would like to be pointed in the right direction and a link to some of that information would be greatly appreciated.