Collision with hexagonal system of bars

[lightarrow]

Don't know if this has already been asked.
A system of six hinged (articulated?) bars, all equal, forming an hexagon is placed on a flat surface. Everything is without friction.

An impulsive force (extremely short time duration, very high intensity, like an elastic collision from rigid bodies) is applied from outside of the system, perpendicularly in the centre of one of the bars, along the surface. As a consequence this bar acquires, immediately after this collision, a speed v in the direction of the force.

Which is the speed at which it moves the bar opposite to this one, in the hexagon, immediately after the collision?

Trying to solve this problem computing all the constraints forces is mind-boggling.
Any idea?

Thank you.
lightarrow

 

[LightHero]

The answer to this question is that the bar opposite to the one that received the impulsive force will move with the same speed, v. This is due to Newton's Third Law of Motion, which states that for every action there is an equal and opposite reaction. Therefore, since the bar that received the impulsive force has been given a speed of v, it will cause the opposite bar to also move with the same speed.