Collisions: Ball with initial velocity is kicked, force of kick?

AI Thread Summary
A 10 g ball with an initial speed of 5 m/s is kicked at a 35° angle, resulting in a final speed of 25 m/s. The discussion revolves around determining the force of the kick, with participants clarifying that this scenario involves impulse-momentum rather than momentum conservation. The correct approach involves using the impulse formula, where impulse equals the change in momentum. There is confusion about the relationship between force, time, and momentum, which is clarified through the distinction between impulse as F*t and change in momentum as p_f - p_i. Understanding these concepts is crucial for solving the problem effectively.
Merlinnair
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Homework Statement


A 10 g ball going at a speed of 5 m/s is kicked, and flies off at an angle of 35° at 25 m/s. What was the force of kick?
Known:
m = 0.0010 kg
vi = 5 m/s
θ = 35°
vf = 25 m/s

Homework Equations


mvi = mvf
F = ma

The Attempt at a Solution


Would this count as an inelastic collision?
In the x direction:
.0010g(5m/s) + m(0m/s) = (.0010 kg + m)(25cos35)

After that, I'm really not sure how to get to the acceleration...
 
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This is an impulse-momentum problem, not a momentum conservation problem. (You'll need the time during which the kick was applied.)
 
In that case, I might have forgotten a variable, as I don't have the question with me. So if I had the time...

Impulse is F/t and change in momentum right?

So then, all I'd have to do is set F/t = p_i - p_f?
 
Merlinnair said:
Impulse is F/t and change in momentum right?
Almost. Impulse is F*t, not F/t.
So then, all I'd have to do is set F/t = p_i - p_f?
Set impulse = Δp. (FYI: Change in something is always final - initial.)
 
Oh, right, typo on the change in part, and I really do need to start memorizing my equations. Thanks for your help!
 
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