Comparing Flux of a Closed Cylinder

AI Thread Summary
The discussion focuses on comparing the electric flux through the ends of a closed cylinder when a negatively charged particle is placed outside its left end. The flux through the left end is positive, as the electric field points outward, while the flux through the right end is negative, indicating the field points inward. The conversation raises questions about the contribution of the curved sides of the cylinder to the total flux. To analyze this, the approach involves computing the flux through differential annuli at both ends and integrating over the respective angles. The comparison of these flux values will clarify the overall behavior of the electric field in relation to the cylinder.
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Homework Statement


A closed cylinder consists of two circular end caps and a curved side. A negatively charged particle is placed outside the left end of the cylinder, on its axis. Compare the flux through the left end of the cylinder with that through the right.


2. The attempt at a solution

I know the field points out of the cylinder on the left end, and into the cylinder on the right, so the flux through the left end is positive while that through the right end is negative. But what above the sides of the curves?
 
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Does the question ask you about the curved sides?
What law tells you how the electric flux from a point charge, through a fixed area, changes with distance?
 
Let
charge located at x = 0
near end locared at x = d
length of cylinder = L
R = radius of ends

1. Compute the flux through a differential annulus for the near end. Integrate from r = 0 to r = R parametrically using θ = arc tan r/d.
2. Do the same for the far end. Realize θ will range from 0 to a smaller number than for the near end.
3. Compare.
 
Thanks !
 
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