- #1
redribbbon
A uniform rod of mass 3.15×10^−2 kg and length 0.380 m rotates in a horizontal plane about a fixed axis through its center and perpendicular to the rod. Two small rings, each with mass 0.250 kg, are mounted so that they can slide along the rod. They are initially held by catches at positions a distance 5.20×10^−2 m on each side from the center of the rod, and the system is rotating at an angular velocity 34.0 rev/min. Without otherwise changing the system, the catches are released, and the rings slide outward along the rod and fly off at the ends.
now
I think that the its just pure conservation of momentum
Iwinitial=Iwfinal
so i do
((1/12)(3.5*10^-2)(.38)^2+2*.25*(5.2x10^-2)^2))
divided by
((1/12)(3.5*10^-2)(.38)^2+2*.25*(.38^2))
and then multiply the result by 34
but i get 0.8109
which is the wrong answer
what i am doing wrong?
now
I think that the its just pure conservation of momentum
Iwinitial=Iwfinal
so i do
((1/12)(3.5*10^-2)(.38)^2+2*.25*(5.2x10^-2)^2))
divided by
((1/12)(3.5*10^-2)(.38)^2+2*.25*(.38^2))
and then multiply the result by 34
but i get 0.8109
which is the wrong answer
what i am doing wrong?
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