Conservation of energy in Gravitation

In summary, the textbook has claimed that in Mars's frame, the energy of the rocket is conserved, while in the Sun's frame, this event is seen as an elastic collision between Mars and the rocket.
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phantomvommand
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Suppose a rocket is moving at radial velocity vr and tangential velocity vt in the Sun's gravitational field. At some time, the rocket enters the gravitational field of Mars (with the above mentioned velocities), and gravitation effects due to the Sun can be ignored. After more time, the rocket leaves the g-field of Mars. Let Mars move at velocity vm with respect to the Sun.

The textbook has claimed that in Mars's frame, the energy of the rocket is conserved, while in the Sun's frame, this event is seen as an elastic collision between Mars and the rocket.

I can see how energy of the rocket is solely conserved in Mars's frame, like how objects in Earth's g-field have their energy conserved basically. But how does the "elastic collision" in the Sun frame work? What would be the equations of conservation of momentum/energy? You guys are welcome to introduce new variables to quantify/better illustrate your explanations. Thank you!
 
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phantomvommand said:
But how does the "elastic collision" in the Sun frame work?
A head on elastic collision with an much heavier object means the speed relative to the heavier object is approximately conserved, just the direction is reversed.

Let v and U be the speeds of rocket and planet moving in opposite directions in the sun's frame. If you simplify the trajectory to a U-turn as shown below:

- In the planet's frame the rocket velocity goes from v+U to -(v+U)
- In the sun's frame the rocket velocity goes from v to -(v+2U)

This is a simple Galilean Transformation (subtracting U from both velocities)

700px-Gravitational_slingshot.svg.png

From: https://wiki.kerbalspaceprogram.com/wiki/Tutorial:_Gravity_Assist

phantomvommand said:
I can see how energy of the rocket is solely conserved in Mars's frame, like how objects in Earth's g-field have their energy conserved basically.
That is actually an approximation, because Mars is accelerated by the rocket, so its frame is not perfectly inertial. This doesn't matter much for energy, but it does for momentum. You can use the common center of mass frame of Mars and rocket to have conservation of energy and momentum.

phantomvommand said:
But how does the "elastic collision" in the Sun frame work? What would be the equations of conservation of momentum/energy?
Here again you have to use the common center of mass frame of Sun, Mars and rocket, to have conservation of energy and momentum.
 
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Note that elastic collisions also conserve energy, by definition.
 
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phantomvommand said:
I can see how energy of the rocket is solely conserved in Mars's frame, like how objects in Earth's g-field have their energy conserved basically. But how does the "elastic collision" in the Sun frame work? What would be the equations of conservation of momentum/energy? You guys are welcome to introduce new variables to quantify/better illustrate your explanations. Thank you!
Another way to describe an elastic collison is one where the separation speed between the two objects is the same before and after the collision. That implies that the KE of each object is conserved in the frame of the other.
 
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PeroK said:
Another way to describe an elastic collison is one where the separation speed between the two objects is the same before and after the collision. That implies that the KE of each object is conserved in the frame of the other.

A common analogy is throwing a ball against a wall that is approaching you:
https://solarsystem.nasa.gov/basics/primer/

Gravity-Assist-Cartoon-1095x502.png
This is also similar to making an effieicent U-turn with a plane in a moving airmass:

 
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FAQ: Conservation of energy in Gravitation

What is the law of conservation of energy in gravitation?

The law of conservation of energy in gravitation states that the total energy of a system of objects interacting through gravitational forces remains constant over time. This means that the total amount of energy in the system cannot be created or destroyed, but can only be transferred or transformed from one form to another.

How does the law of conservation of energy apply to gravitational potential energy?

The law of conservation of energy applies to gravitational potential energy by stating that the sum of an object's kinetic energy and gravitational potential energy must remain constant. As an object moves closer to a gravitational source, its gravitational potential energy decreases while its kinetic energy increases, and vice versa. This ensures that the total energy of the system remains constant.

Can the law of conservation of energy be violated in gravitation?

No, the law of conservation of energy cannot be violated in gravitation. This is because energy is a fundamental property of the universe and is always conserved. Any apparent violations of this law can be explained by energy being transferred or transformed into different forms, but the total amount of energy remains constant.

How does the law of conservation of energy affect orbits in gravitation?

The law of conservation of energy plays a crucial role in determining the shape and stability of orbits in gravitation. In a closed orbit, an object's kinetic energy and gravitational potential energy remain constant, resulting in a stable circular or elliptical orbit. If an object's energy changes, it can either escape the gravitational pull or crash into the central body.

What are some real-world applications of the law of conservation of energy in gravitation?

The law of conservation of energy in gravitation has many practical applications. For example, it is used in satellite and spacecraft trajectories, planetary orbits, and understanding the dynamics of celestial bodies. It also plays a crucial role in the study of astrophysics, including the formation and evolution of galaxies and the universe as a whole.

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