Converting Cartesian to Cylindrical Coordinates

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The discussion focuses on converting Cartesian coordinates to cylindrical coordinates, specifically for two equations, A and B, given at certain points. It highlights the confusion around transforming these equations, emphasizing the importance of understanding the unit vectors associated with cylindrical coordinates, which vary based on the point in space. The initial attempts at conversion yielded Cartesian coordinates but did not address the vector representation in cylindrical form. Participants suggest consulting textbooks for detailed explanations and examples, as the provided link may not clarify the concepts adequately. Understanding the relationship between the unit vectors and the specific point is crucial for accurate transformation.
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Homework Statement



Hi i have a question that how to convert the co-ordinates according to following statement?
Its no difficult to solve the simple conversion but the bold one are confusing me.


A=4x-2y-4z
Transform it into cylindrical co-ordinate system at P (ρ=4, ϕ=120o ,z=2)

B=15x+10y
Transform it into cylindrical co-ordinate system at P(x=3, y=4, z=-1)





2. The attempt at a solution

Equations for converting Cartesian to cylindrical coordinates:

r= [x2 + y21/2
ϕ= tan-1= y/x
z=z

by putting values
For First question:
r=√20=4.472
ϕ= -26.57
z=-4

For Second question:
r= 18.03
ϕ= 33.69
z=0
 
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This is common point of confusion. What you've done is convert the Cartesian coordinates (4, -2, -4) to the equivalent cylindrical coordinates. What the problem is asking you to do, however, is different.

Take a look at the diagram at the start of this page:

http://mathworld.wolfram.com/CylindricalCoordinates.html

At each point, there are associated unit vectors ##\hat{\rho}##, ##\hat{\phi}##, and ##\hat{z}##. Their directions depend on which point you're at. For example, if you're at the point (1, 0, 0), ##\hat{\rho}## would point along the +x-direction, and ##\hat{\phi}## would point in the +y direction. If you're at the point (0, 1, 0), ##\hat{\rho}## would point in the +y direction, and ##\hat{\phi}## would point in the -x direction.

Given the information in bold, you can figure out what ##\hat{\rho}## and ##\hat{\phi}## are. ##\hat{z}## always points in the +z direction. Once you know what the unit vectors are equal to, you're supposed to express the vectors A and B in terms of them.
 
unfortunately i can't understand from that given link, kindly give an example by solving one of the equation or any of. . .
 
Sorry, we don't do your homework for you here. If you can't see what I tried to explain from the diagram, I suggest you consult your textbook for a more detailed explanation.
 
I doesn't mean that, i just want to say that, if you please tell this by example by taking any random point P, if such an example is given on textbook, i don't need to refer from internet
 
My point was that I would have liked to see even a minimal attempt from you to try understand what's going on instead of simply saying "I don't get it."

At each point, there are associated unit vectors ##\hat{\rho}##, ##\hat{\phi}##, and ##\hat{z}##. Their directions depend on which point you're at. For example, if you're at the point (1, 0, 0), ##\hat{\rho}## would point along the +x-direction, and ##\hat{\phi}## would point in the +y direction. If you're at the point (0, 1, 0), ##\hat{\rho}## would point in the +y direction, and ##\hat{\phi}## would point in the -x direction.
Say you have a vector field ##\vec{V}(\vec{r})##, and at both ##\vec{r}=(1, 0, 0)## and ##\vec{r}=(0, 1, 0)##, it points in the +x direction.

At the point (1, 0, 0), you'd say ##\vec{V}(1, 0, 0) = \hat{\rho}##. At the point (0, 1, 0), however, the basis vectors point in different directions. In this case, you'd have ##\vec{V}(0, 1, 0) = -\hat{\phi}##.
 
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