Creating a new compound (involving K,Ca,H,N). Is it possible?

[ProjectFringe]

Thanks again everyone for your responses to my many questions!

I think the following steps could have a small probability of success in creating the compound I want. This assumes that this compound is being created in a lab and at an atomic level. Therefore, the only things which can react are what is listed in each step (one atom of each).

I know this is long and difficult to read, but I did my best to explain my thinking as best I could and would appreciate any feedback!Step 1. NH⁺ forms double bond with ⁴⁰KN
The isotope of potassium used is ⁴⁰K. ⁴⁰K is a natural, long-lived radioactive isotope of potassium. The dots represent unpaired electrons, and the numbers represent the number of electrons in the outer shell of each nitrogen. This compound is unbalanced and unstable.

^.H⁺N=NK:
7 8

Step 2. ⁴¹Ca+ is added to the original compound, N₂KH⁺+ ⁴¹Ca⁺
The isotope of calcium used is ⁴¹Ca. ⁴¹Ca is a natural, long-lived radioactive isotope of calcium. This compound is balanced, but unstable because ⁴¹Ca will naturally decay.

Ca⁺H⁺N=NK:
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Step 3. ⁴¹Ca⁺ decays to ⁴⁰K and H⁺.
Under normal circumstances, ⁴¹Ca usually decays to ⁴¹K through electron capture. However, in this case since the cation of ⁴¹Ca is being used, only one electron is available in the outer shell of ⁴¹Ca⁺. This electron is strongly attached to the nitrogen, which is now balanced, making it unavailable to the ⁴¹Ca⁺. Therefore, using an electron from an inner shell would result in an undesirable total number of electrons for ⁴¹Ca⁺. For this reason, in this instance, I believe electron capture may not be the best option. However, ⁴¹Ca⁺ still must decay. Other ways of decay, such as neutron activation or beta decay, are either not available or lead to a more unstable state. Therefore, with the energy available from the decay of ⁴¹Ca⁺ and possibly the decay of the current ⁴⁰K, ⁴¹Ca⁺ removes a proton, creating another ⁴⁰K, a long-lived radioactive isotope of potassium (even longer-lived than ⁴¹Ca) and a free proton (H⁺). This proton joins the available lone pair, and ⁴⁰K replaces ⁴¹Ca⁺. This creates the most balanced version of this compound to date. However, it is still unstable because ⁴⁰K will continually decay.

H⁺KN=NKH⁺
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Step 4. The original ⁴⁰K decays to ⁴⁰Ca through beta decay
The original ⁴⁰K has been naturally decaying to ⁴⁰Ca. However, with the creation of ⁴⁰Ca, another electron is now available. Therefore, the ⁴⁰Ca unbalances the formerly balanced compound.

H⁺KN=NH⁺ Ca
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Step 5. ⁴⁰Ca decays to ⁴¹Ca⁺ through neutron activation
The decay of ⁴⁰Ca to ⁴¹Ca is a natural process, under the right conditions, even though ⁴⁰Ca is stable. Similarly, in this case, the desire to lose the extra electron (created from the decay of ⁴⁰K to ⁴⁰Ca) causes ⁴⁰Ca to use this extra electron, in combination with the available proton (H⁺), to decay to ⁴¹Ca⁺. This occurs through, what would basically be, neutron activation. This process rebalances the compound, creating essentially the same compound as in step 2.

H⁺KN=NCa⁺:
8 8

It also allows for a continuous cycle of steps 2 through 5, creating reflections of itself as it passes through a neutral state.

Step 5 (or 2) > Step 3 > Step 4 > Step 5 (or 2) > Step 3 > Step 4 > back to the beginning
H⁺KN=NCa⁺: > H⁺KN=NKH⁺ > CaH⁺N=NKH⁺ > :Ca⁺N=NKH⁺ > H⁺KN=NKH⁺ > H⁺KN=NH⁺Ca > back to the beginning
+ > N > - > - > N > + > back to the beginning

Below is an image of the above because I couldn't get the spacing right

 

[Borek]

It won't work, mostly because this is not how it works.

Sorry for being blunt, but basically you are mixing misunderstood concepts with wishful thinking. You treat statements like "in some peculiar conditions maybe" as "Aha! so that's the proper course of action", and you fail to realize there are many contradicting assumptions in your propositions. Actually so many, it is not even possible to start explaining why they are wrong without a long and serious lecture about basic concepts.

To use an analogy: imagine someone starts explaining to you a new procedure of building something stating: "first, we will put this heap of sand in the air, then we will shot a bucket of water at it to convert it into concrete". Well, sand doesn't hang in the air just like that, adding water is not enough to make a concrete so it will be obvious to you that this can't work. To some extent that's how your procedure looks like to us.

If that's your hobby project make it into something bigger: start by getting an undergraduate level of understanding chemistry. No shortcuts, as they will only produce more confusion, just three years of serious, systematic study. You will learn why many of the things you propose look just like random combinations of unrelated facts.

I am locking the thread. There is not much worth discussing here.