Creation/Annihilation operator help

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The discussion focuses on the differentiation of an integral involving an annihilation operator, specifically the equation ∂/∂t ∫^t_0 e^{i ω(t-u)}âb(u) du = âb(t). The user seeks clarification on how to derive this result, suggesting that a delta function may be involved. They reference a calculus theorem that relates the differentiation of an integral to the function being integrated. By applying this theorem, they identify the relevant functions and conclude that the derivative simplifies to the desired form. The explanation effectively demonstrates the application of calculus to quantum mechanics concepts.
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Homework Statement


I'm trying to go through something shown in a lecture and the part I'm stuck on is shown here.
\frac{\partial}{\partial t}\int^t_0 \mbox{du }e^{i \omega(t-u)}\hat{b}(u)=\hat{b}(t)

\hat{b}(u) is an annihilation operator

The Attempt at a Solution


Can someone explain how this step is made? Obviously a delta function has to come in somewhere but I don't know how to do that with a derivative (only another integral).
 
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this follows from a theorem in calculus

Theorem: Suppose that a function g:[c,d]\rightarrow [a,b] (not necessarily a
onto function) is differentiable, and a function f:[a,b]\rightarrow \mathcal{R}
is continuous. If

H(t)=\int_a^{g(t)} f(u)\, du

with t\in [c,d], then H is differentiable and

\large H'=(f(g(t))g'(t)

in your example

f(u)=e^{i \omega(t-u)}\hat{b}(u)

and g(t)=t

so

H'(t)=(f(g(t))g'(t)

g'(t)=1

so

H'(t)=f(t)

which gives what you are seeking
 
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