Current of Phasor going in CCW direction

AI Thread Summary
The discussion centers on determining the correct representation of a current phasor rotating counterclockwise (CCW) in the equation vo(t). A participant questions whether the current should be expressed as -5cos(10t - 45) instead of 5cos(10t - 45) due to its CCW direction. It is clarified that inverting the amplitude corresponds to a 180-degree phase shift, but to change the rotation direction, a negative sign must be applied differently in the equation. The conversation emphasizes understanding how each term in the equation influences the function's behavior. Ultimately, the correct approach to represent the phasor's direction is crucial for accurate analysis.
smstepanic
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Hi,

I feel I have solved this problem correctly (solving for vo(t)), however since the current is going in the ccw direction, would this make the current -5cos(10t - 45) versus 5 cos(10t -45)? This may be a simple question, so I am just making sure. Thanks!
 

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smstepanic said:
Hi,

I feel I have solved this problem correctly (solving for vo(t)), however since the current is going in the ccw direction, would this make the current -5cos(10t - 45) versus 5 cos(10t -45)? This may be a simple question, so I am just making sure. Thanks!
Inverting the amplitude is the same as adding a 180-degree phase shift. To make the rotation direction different, you need a negative sign in a different place...
 
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berkeman said:
Inverting the amplitude is the same as adding a 180-degree phase shift. To make the rotation direction different, you need a negative sign in a different place...

I think I understand. A 180 degree phase shift would apply to the -45 degrees. So 5cos(10t + 135)?
 
smstepanic said:
I think I understand. A 180 degree phase shift would apply to the -45 degrees. So 5cos(10t + 135)?
Um, no, that's not what I meant.

Regardless of the problem you posted, if you want the phasor to rotate in the opposite direction, you need to multiply by -1 where in the equation? Think about how each term in the equation affects the function...
 
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