MHB Definition of H in pulley diagram

[Dustinsfl]

Why can $H = \left(\ell - \frac{b}{\sin\theta}\right)$ where $\ell$ is the length of the rope. (everything is frictionless.)
http://img690.imageshack.us/img690/579/pulley.png

 

[Evgeny.Makarov]

Why can $H = \left(\ell - \frac{b}{\sin\theta}\right)$ where $\ell$ is the length of the rope.

Because $\frac{b}{\sin\theta}$ is the length of the diagonal stretch of the rope.

 

[Dustinsfl]

Because $\frac{b}{\sin\theta}$ is the length of the diagonal stretch of the rope.

Due to all your help prior with tikz, I have been making pictures like this and better since last summer.

 

[Evgeny.Makarov]

Glad to hear that. The picture looks nice!

 

[Dustinsfl]

Glad to hear that. The picture looks nice!

If you check out the math notes section and look at the pdfs I created, you will some more Latex pictures I created from what I learned from you.