Derive the wave equation for fields E, B from the potentials

AI Thread Summary
The discussion focuses on deriving the wave equations for the electric (E) and magnetic (B) fields from scalar and vector potentials in vacuum. The user successfully derived the wave equation for the B field using the curl of the vector potential A but encountered difficulties with the E field. They propose that the derivation involves combining the definitions of E, the wave equations for the potentials, and the Lorenz gauge condition. The user confirms that taking derivatives inside the Laplacian and time derivative is permissible under the assumption of well-behaved functions. The conversation concludes with a reassurance that the approach is valid, emphasizing the importance of understanding the conditions under which these mathematical operations are allowed.
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I'm studying for my electrodynamics exam and one of the past exam questions is:

From the scalar and vector potentials, derive the homogenous wave equations for E and B fields in vacuum.

I did derive the wave equation for the B field by simply taking the curl of the homogenous wave equation for the vector potential A. But I got stuck deriving the wave equation for the E field. I think it has to come from a tricky combination of the following four equations:
1) Definition of the E field E = -Φ - ∂A/dt
2&3) Wave equations for Φ and A
4) Lorenz gauge condition: ∇.A - (1/c^2)(∂^2Φ/∂t^2) = 0

Any help is appreciated!
 
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If Φ satisfies the wave equation, can you show that -Φ also satisfies the wave equation?
 
Hmm, so I write -(ΔΦ-(1/c^2)(∂^2Φ/∂t^2))=Δ(-Φ)-(1/c^2)(∂^2(-Φ)/∂t^2)=0. And this operation (i.e, taking nabla 'inside' the Laplacian and the partial time derivative) is allowed, right? There are no restrictions on it as far as I know but I'm not 100% sure.

Then I perform the same trick for -∂A/∂t. Similarly, I take the partial derivative inside (again, assuming it's allowed), showing the equation is satisfied for -∂A/∂t. Then add up the new equations, use formula 1) above and done?
 
That was what I wasn't 100% sure. Thanks!
 
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