Derive time-dependent current for circuit

AI Thread Summary
The discussion focuses on deriving the time-dependent current I(t) for an LC circuit, where an inductor L and capacitor C are involved. The circuit is initially open, and the switch closes at t=0, prompting the need to apply Kirchhoff's Voltage Law to analyze the circuit. The voltage equations for the inductor and capacitor are established, leading to a second-order differential equation. The solution to this equation involves oscillatory functions, resulting in I(t) expressed as a combination of cosine and sine functions. Constants A and B in the solution can be determined using initial conditions.
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Homework Statement


Derive an expression for the current I(t) as a function of time for the following circuit:

____ \____
|..... |
&..... -
& .....-
| ...|
___________

This circuit may be a bit unclear - the && is an inductor L, the - - is a capacitor C, and the top part is a switch that is open for t<0 and closed at t=0. And the ... are filler.

Homework Equations



I have no idea I am struggling incredibly.

The Attempt at a Solution



Help help please
 
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1. Use Kirchoff's Voltage Law (sum of voltages around the loop of the circuit):2. However, we need to determine the voltage across the inductor and capacitor.
Just do research, the voltage of the inductor is:

V_L = Ldi/dt

V_C = (1/C) integral (idt)3. Using KVL: Ldi/dt + (1/C)integral(idt) = 04. We need to turn this one to differential equations. So we differentiate term by term

Ld^2i/dt^2 + (1/C)i = 05. Use methods of differential equation to solve for i with respect to t.

Lm^2 + (1/C) = 0

m^2 + 1/(L*C) = 0; m = +- j/(L*C)

I(t) = Acos(t/(LC)) + Bsin(t/(LC))6. The constants A and B can be derived using initial conditions.

See here for more details:

http://en.wikipedia.org/wiki/LC_circuit
 
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