- #1
Paradise Jack
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1. Derive this equation
t = 2(vi)/g*sin(theta)
where vi isinitial velocity, and g is acceleration due to gravity
2. Implicit differentiation, possibly gravity as a constant.
t = 2(vi)/v*sin(theta)
dt/d(theta) = 2(vi)/g * dt/d(theta)(sin(theta))
dt/d(theta) = 2(vi)/g * cos(theta)
Basically, I said that velocity and gravity were constants as well as 2. Would this be a correct derivation of the listed formula
t = 2(vi)/g*sin(theta)
where vi isinitial velocity, and g is acceleration due to gravity
2. Implicit differentiation, possibly gravity as a constant.
The Attempt at a Solution
t = 2(vi)/v*sin(theta)
dt/d(theta) = 2(vi)/g * dt/d(theta)(sin(theta))
dt/d(theta) = 2(vi)/g * cos(theta)
Basically, I said that velocity and gravity were constants as well as 2. Would this be a correct derivation of the listed formula
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