Designing a Ballistic Spring System for Measuring Bullet Speed

AI Thread Summary
The discussion focuses on designing a ballistic spring system to measure bullet speed, involving a bullet of mass m fired into a block of mass M, which then compresses a spring with spring constant k. The key equations used include conservation of momentum and energy principles, leading to the derivation of the bullet's speed VB in terms of m, M, k, and d. The final expression for VB simplifies to VB = √((m + M)kd^2/m^2), matching the book's answer. The participant expresses frustration over the complexity of the problem but ultimately arrives at the correct solution. This highlights the importance of careful factorization in physics problems.
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Homework Statement


You have been ask to design a "ballistic spring system" to measure the speed of bullets. A bullet has a mass of m is fired into a block with mass M. The block, with the embedded bullet, then slides across a frictionless table and collides with a horizontal spring whose spring constant is k. The opposite end of the spring is anchored to a wall. The spring's maximum compression is d is measured.

A. Find a expression for the bullet's speed VB in terms of m, M, k, d.
B. Not help is needed
C. " "


Homework Equations


I think,
Pi = Pf
Ki + Ui = Kf + Uf


The Attempt at a Solution



mVB + MV0 = (m + M)V1

MV0 goes to 0

Equation 1. VB = (m + M)V1
......m
________________________
.5(m + M)V1^2 + (m + M)gy1 = .5(m + M)V2^2 + (m + M)gy2 + .5kd^2

Having the Y axis start at the bullets height - (m + M)gy1, (m + M)gy2 go to 0

.5(m + M)V2^2 I think goes to 0

Equation 2. V1 = Sq. Rt.(kd^2/(m + M))

Plug 1 into 2

VB = Sq. Rt. ((m + M)^2kd^2/ m^3 + Mm^2)


I don't know. I tried so many things... just not getting it...
 
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Wow, just realize if i would have factor better:
VB = Sq. Rt. ((m + M)^2kd^2/ m^3 + Mm^2)

Becomes VB = Sq. Rt.((m + M)kd^2/m^2)

Which is the answer the book had.
 
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