Determine Mass moment of inertia about any axis given Ixx...

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To calculate the mass moment of inertia about any axis using known values of Ixx, Iyy, and Izz, one can utilize the properties of the moment of inertia as a symmetric rank two tensor. The transformation between coordinate systems can be achieved using a rotational transformation matrix, which modifies the tensor components according to the equation I' = A I A^T. This method allows for the accurate transfer of body properties from one coordinate system to another. It is important to recognize that the moment of inertia is a rank 2 tensor, not a vector. Understanding this distinction is crucial for proper calculations in human motion analysis.
Mohsen Diraneyya
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Hello,

I am analyzing human motion. for each body segment, I have measured values for Ixx, Iyy, and Izz in local coordinate system. I want to transfer all body properties from one coordinate system to another using a transformation matrix.

My question is that
, is there a way to calculate mass moment or inertia about any known axis, given the mass moment of inertia about the three primary axes? Ixx, Iyy ans Izz

Thanks.
 
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Yes, the moment of inertia is a symmetric rank two tensor. Given the principal directions and their corresponding moments uniquely defines this tensor.
 
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Orodruin said:
Yes, the moment of inertia is a symmetric rank two tensor. Given the principal directions and their corresponding moments uniquely defines this tensor.
Does that mean I can simply use rotational transformation matrix as any other vector to get new moments of inertia ?
 
Mohsen Diraneyya said:
Does that mean I can simply use rotational transformation matrix as any other vector to get new moments of inertia ?
No, it is a rank 2 tensor, not a vector. You marked this thread "A" so I assumed you were familiar with tensors. Written in matrix form, the components of a rank 2 tensor transform according to
$$
I' = A I A^T,
$$
where ##I## contains the components of the moment of inertia tensor in old system, ##I'## its components in the new system, and ##A## is the rotation matrix connecting the systems.
 
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My bad. Thanks A lot:ok:
 
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