Determine resolution of use by modelling it as single slit

AI Thread Summary
The discussion focuses on modeling the pupil of the eye as a single slit to determine its resolution capabilities. The problem states that the eye can distinguish two objects separated by an angle of 0.00015 radians, given a wavelength of 500nm and a pupil diameter of 4mm. Participants suggest using the pupil diameter for the slit width and emphasize the need to account for two light sources in the intensity equation. The conversation highlights the importance of considering intensity changes and the combined diffraction pattern from both sources. Overall, the thread seeks clarification on applying the intensity equation to solve the problem effectively.
twinklestar28
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Homework Statement



Model the pupil of the eye using a single slit. If the eye is able to notice changes in intensity of 20% show that it can distinguish two objects separated by an angle of 0.00015 radians if =500nm and diameter=4mm.



Homework Equations


I=Iosin^2((π/λ)asinθ)/ ((π/λ)asinθ)^2
sin θ=λ/a


The Attempt at a Solution



I attempted to find a (width) from the intensity equation but it doesn't seem to work, so I am unsure of how to start the calculation, the question is worth 4 marks, any help would be appreciated :)
 
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twinklestar28 said:

Homework Statement



Model the pupil of the eye using a single slit. If the eye is able to notice changes in intensity of 20% show that it can distinguish two objects separated by an angle of 0.00015 radians if =500nm and diameter=4mm.

Homework Equations


I=Iosin^2((π/λ)asinθ)/ ((π/λ)asinθ)^2
sin θ=λ/a

The Attempt at a Solution



I attempted to find a (width) from the intensity equation but it doesn't seem to work, so I am unsure of how to start the calculation, the question is worth 4 marks, any help would be appreciated :)
Looks like for the slit width you are to use the diameter of the pupil ("Model the pupil of the eye using a single slit")

You wrote I(θ) for a slit illuminated by a single source. You need to account for the fact that there are two sources, separated by an angle of 0.00015 radians.
 
O ok so the equation would be

I=Iosin^2((π/λ)asinθ-∅)/ ((π/λ)asinθ-∅)^2

it gives a hint to consider the intensity halfway between the peaks of the two images so i did

((π/λ)asin(θ-∅)) = ∏/2

but where do i put the intensity change of 0.2% to get (θ-∅) = 0.00015?
 
twinklestar28 said:
O ok so the equation would be

I=Iosin^2((π/λ)asinθ-∅)/ ((π/λ)asinθ-∅)^2
That's the intensity of a single source that is located an angle ∅ away from the central axis.

But we have two sources. Let's say one of them is an angle ∅ away from the central axis, and one of them is on the central axis. You need to consider the intensity due to each source, and combine them to get the intensity in the combined diffraction pattern.
 
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