Determining the equation of a curve

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The problem involves finding the equation of a curve traced by a point P (x,y) based on its distances from two fixed points A (-1,1) and B (2,-1). The key relationship is that the distance from point A to P is three times the distance from point B to P. To solve this, one should apply the distance formula to express these distances mathematically. By setting the distance from A to P equal to three times the distance from B to P, the equation of the curve can be derived. This approach will lead to the required equation for the curve.
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Homework Statement



A curve is traced by a point P (x,y) which moves such that its distance from the point A (-1,1) is three times its distance from the point B (2,-1). Determine the equation.

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The Attempt at a Solution



used distance formulas to find A is the squareroot of 13 away from B.

how do i find the curve
 
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I would try to translate what the problem says in words into equations.

You're told that the distance from point A to point P is always 3 times the distance from point B to point P.

So it seems to me that the way to proceed is to write down an expression for the distance from A to P and set it equal to the expression for the distance from B to P multiplied by 3.
 
You should try applying the distance formula for the problem as you described it. That should help you to start.
 
The working out suggests first equating ## \sqrt{i} = x + iy ## and suggests that squaring and equating real and imaginary parts of both sides results in ## \sqrt{i} = \pm (1+i)/ \sqrt{2} ## Squaring both sides results in: $$ i = (x + iy)^2 $$ $$ i = x^2 + 2ixy -y^2 $$ equating real parts gives $$ x^2 - y^2 = 0 $$ $$ (x+y)(x-y) = 0 $$ $$ x = \pm y $$ equating imaginary parts gives: $$ i = 2ixy $$ $$ 2xy = 1 $$ I'm not really sure how to proceed from here.
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