Did I Make a Mistake in My Spring Constant Calculation?

AI Thread Summary
The discussion centers on calculating the spring constant and theoretical period of oscillation for a spring. The initial calculation yielded a spring constant of 9.1 N/m and a theoretical period of 2.9 seconds, which did not match real-life measurements. It was identified that the mass used in the calculation should be in kilograms, not Newtons, leading to confusion in the units. By converting the mass from Newtons to kilograms, the calculations became more accurate, resulting in a period closer to the observed value. Emphasizing the importance of unit consistency in physics calculations is crucial for accurate results.
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The goal is to measure the spring constant of a spring and then calculate a theoretical period of the oscillation and compare the results to a real life measurement.

Extension of spring A:
Neutral: 52 cm
1 N: 41 cm
2 N: 30 cm
F = kx
k = 9.1 N/m

10 oscilliations = 9.26 seconds

Calculating the theoretical period for 2 Newton:
t=2pi*sqrt(m/k)
t=2pi*sqrt(2/9.1)=2.9 which is completely wrong compared to the real life result.
If i set k to 91 instead of 9.1 the resulting period is 0.93, much closer to reality.

Have I botched up the units along the way or what have I done wrong?

I'd be very greatful for help.
 
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squashen said:
The goal is to measure the spring constant of a spring and then calculate a theoretical period of the oscillation and compare the results to a real life measurement.

Extension of spring A:
Neutral: 52 cm
1 N: 41 cm
2 N: 30 cm
F = kx
k = 9.1 N/m

10 oscilliations = 9.26 seconds

Calculating the theoretical period for 2 Newton:
t=2pi*sqrt(m/k)
t=2pi*sqrt(2/9.1)=2.9 which is completely wrong compared to the real life result.
If i set k to 91 instead of 9.1 the resulting period is 0.93, much closer to reality.

Have I botched up the units along the way or what have I done wrong?

I'd be very greatful for help.

On the calculation of the natural frequency, what units does "m" have? What were the units of the "2" that you put into the numerator in side the square root?
 
the unit M is in Newtons, and its for measuring the oscilliation of the spring with a spring constant of 9.2 when its weighed down with 2 Newtons
 
I believe I´ve found a solution, by converting the unit m from Newtons to kg it looks more correct. Sorry for the inconvenience!
 
squashen said:
the unit M is in Newtons, and its for measuring the oscilliation of the spring with a spring constant of 9.2 when its weighed down with 2 Newtons

Are you sure?

t has what units? sec ? right?

What units do you get for "t" when you use M with units of Newtons?
 
squashen said:
I believe I´ve found a solution, by converting the unit m from Newtons to kg it looks more correct. Sorry for the inconvenience!
Yup! "m" is the mass of the bob in kg. Newtons are units for the force that the bob exerts. F = m*g

This is why it is always a good idea to work with units on your numbers. You would have seen that you got nonsense units for the period of oscillation if you had kept units of "m" and "k".
 
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