Did I Solve the Vertical Post Problem Correctly Using SOH CAH TOA?

AI Thread Summary
The discussion centers on solving the vertical post problem using trigonometric principles, specifically SOH CAH TOA. The user initially calculated an angle of 33 degrees for Theta but was corrected, as the vertical components of the tension in the cables do not need to be equal. Instead, the correct angle, as confirmed by calculations, is 63 degrees, derived from balancing the horizontal components of the tensions. The explanation clarifies that the vertical post remains upright due to the balance of forces, with the tension in the cables providing stability. Understanding these principles is crucial for accurately solving similar physics problems.
Ryan Lau
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Homework Statement


A vertical post is held in place by two cables as shown.

Homework Equations


SOH CAH TOA

The Attempt at a Solution


http://postimg.org/image/6rgssb1j5/

The answer in the textbook is 63 degrees. Is this an issue or did I do something terribly wrong?
 
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The tension in the cables keep the post in vertical position. Its top point can not move sideways, the horizontal components of the tensions balance each other.
The vertical components do not need to be equal, as they are balanced by the force from the ground.
 
ehild said:
The tension in the cables keep the post in vertical position. Its top point can not move sideways, the horizontal components of the tensions balance each other.
The vertical components do not need to be equal, as they are balanced by the force from the ground.
Unfortunately, I do not fully comprehend this explanation. My question is why 33 degrees is not the correct angle for Theta.
 
Ryan Lau said:
Unfortunately, I do not fully comprehend this explanation. My question is why 33 degrees is not the correct angle for Theta.
You calculated theta from the condition that the vertical components of the tensions are equal, which is wrong .
 
ehild said:
You calculated theta from the condition that the vertical components of the tensions are equal, which is wrong .

I believe I understand this comment now.

Overview:
To keep the vertical post upright, both the left and right side of the ground by the tensional strings will be equal to each other.

1500cos50 = 964.1814 N = Adjacent Side (floor)
Cos Inv. (964.1814/2100) = 62.6688 N (angle required to keep the pole upright)
 
And the rounded value is 63°.
 
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