Dipole in a nonuniform electric field problem

AI Thread Summary
The discussion revolves around calculating the force and torque on a dipole in a nonuniform electric field created by a point charge. The dipole consists of two charges separated by a distance, and the point charge is positioned far from the dipole. Participants agree on the need to treat the dipole charges as point charges and analyze the force components, noting that the x-component cancels out. The correct expression for the net y-component of the force is provided, emphasizing the importance of the assumption that the distance r is much greater than s. The conversation highlights the necessity of incorporating this assumption into the calculations for accurate results.
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Homework Statement


A point charge Q is held at a distance r from the center of a dipole that consists of two charges ±q separated by a distance s. The dipole is initially oriented so that Q is in the plane bisecting the dipole. Assume that r≫s.

A) Immediately after the dipole is released, what is the magnitude of the force on the dipole?

B) Immediately after the dipole is released, what is the magnitude of the torque on the dipole?

Homework Equations

The Attempt at a Solution


[PLAIN]https://lh3.googleusercontent.com/krQ_JEzmRURs4ZqAkRwrapePDCVyz9DBcELyMJ8-tY1g2JYfSLGdkD4lv4_F_2FaaeXrNoN-ZofGqnvD3VNp8AgsogPnk_kYrS2RL9SY5A6K-q9RTfBwq5_Nv_exlvGk5w_Ui0p2kXAdQa1Jw005jR1eRS9G-0lFjnzhD7CfsHB8-pmm0Kxj-BRM_MQbHapBvyIVizorUYPVqCZNcPo1I8I0u83mzPTSJJdylwMoiC2qDsochCphoyNwRT62P_0p_VF0SKk2qpIhhLIdGO9EUow30nxJjp4EvvSKOMZGSaHl-aXsbewtiwn9ky2DmswaV_GOlaW2UFAhDKbytrYhK9GJ-kyP_PLobfQ_jyhIkKldBX29OF8DUKXyodk6Q4n3N5aW1X10msWQ_tzuchKdsmubrePdPNWxTWIHfLr4z9PL4NeXi5BaCm7QSaWWAyAWmRTkJwUx7AE9zwLyqdBmrwSxZIgZlK2z5_LM8rlKqCK3XdixKgaDBS9tOzi4wLe9Gp96Jn7gJpG_m5EwwgaA3LVHTWIWAWFvqzb_FXTW86j-81g_mAdb2Xltz2xyBYoA_Ozaai1Q46fI5-cPOp7f_rezMCPQ5gmLG-jD6g6m-KSyFMMzCkuT=w497-h662-no[/B]

I treated the two charges on the dipole as point charges and then found the force vectors acting on them. Then I broke down the forces into their components and added them. The x components canceled and I was left with just a y component. For some reason this is wrong, though.
 
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It is not easy to read what the y-component is. Can you use LaTeX to write it down? I agree that the x-component is zero.
 
kuruman said:
It is not easy to read what the y-component is. Can you use LaTeX to write it down? I agree that the x-component is zero.

Here is the net y-component of the force.

\frac{Qqs}{4\pi\epsilon_{0}(r^2+\frac{s^2}{4})^{3/2}}
 
I suspect that they want you to incorporate their specified assumption: Assume that r≫s
 
gneill said:
I suspect that they want you to incorporate their specified assumption: Assume that r≫s
Exactly what I was about to type in. Before you do that, factor out of the radical r in the denominator.
 
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