Dipole of Magnetic field in polar coordinates

AI Thread Summary
The discussion focuses on deriving the magnetic field expressions in spherical coordinates from the vectorial form of the magnetic dipole. The user struggles with the scalar product and converting the magnetic field components, seeking guidance on the process. It is suggested to use spherical coordinates instead of cylindrical ones for the calculations. Key points include the relationships for the radial and angular components of the magnetic field, specifically B_r and B_θ. Overall, the user is looking for clearer instructions on how to manage these transformations effectively.
mahblah
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Homework Statement


Hi everybody... i have a bad problem with my brain:

starting from the Vectorial form of the magnetic dipole:

\vec{B}(\vec{r}) =\frac{\mu_0}{4 \pi} \frac{3 \vec{r} ( \vec{r} \cdot \vec{m}) - r^2 \vec{m}}{r^5}

Homework Equations



i want to derive the spherical expressions, with \vec{m} parallel with z axes

<br /> x = r \cos \theta; y = r \sin \theta; z=z<br />


The Attempt at a Solution



I don't know what to do... I've tried to write B_r = \sqrt{(B_x)^2 + (B_y)^2} ... but i fail...
the solution should be:

<br /> B_r = \frac{\mu_0}{4 \pi} \frac{2 \cos \theta}{r^3}<br />

<br /> B_\theta = \frac{\mu_0}{4 \pi} \frac{\sin \theta}{r^3}<br />


i don't know how to manage the scalar product, i feel really dumb and I am sorry for the low quality of my question,

just some general indication about what to do would be sufficient,

thank u so much.

mahblah.
 
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mahblah said:
<br /> x = r \cos \theta; y = r \sin \theta; z=z<br />

You should use spherical coordinates rather than cylindrical coordinates. See attached figure.

Note that ##B_r = \vec{B}\cdot\hat{r}## and ##B_\theta = \vec{B}\cdot\hat{\theta}##

So, you'll need to consider what you get from ##\vec{r}\cdot\hat{r}##, ##\vec{m}\cdot\hat{r}##, ##\vec{r}\cdot\hat{\theta}##, and ##\vec{m}\cdot\hat{\theta}##
 

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:)

Thank u so much TSny!
 
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