Double Slit Diffraction Problem

AI Thread Summary
The discussion focuses on solving a double slit diffraction problem encountered in an exam. The original poster attempted to find the first maximum's position using Pythagorean theorem and arctan calculations but struggled with the correct approach. Key insights emphasize that constructive interference occurs when the path difference between light rays is a whole number of wavelengths, defining the central maximum as the zeroth maximum. The conversation also highlights the importance of understanding the relationship between the distance from the slits to the screen and the path differences for maxima. Ultimately, the correct method involves applying the appropriate formulas for path differences in diffraction scenarios.
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I had this problem on my exam and I was pretty sure i knew what to do but it couldn't come up with the right answers.
I diagrammed the problem and showed the way i tried to solve it in blue. Can someone tell me where i went wrong?
W6xA170.png


Basically i found the length the of the first maximum off the center. i used Pythagorean's theorem to find D2. Then subtracted the two distances to find the difference. I then took the arctan of that distance divided by D1.
 
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You way over-thought the problem.
Start from the physics: what is the condition that makes a maximum?
 
the center of a maximum is complete constructive interference from two rays of light?
 
the center of a maximum is complete constructive interference from two rays of light?
... good - so what is the condition for constructive interference in terms of the path lengths?
 
wouldn't it be the wavelength plus by any integer being multiplied by the wavelength?
 
wouldn't it be the wavelength plus by any integer being multiplied by the wavelength?
Almost: the path difference has to be a whole number of wavelengths for constructive interference.
This makes the central maximum the zeroth maximum ... with the 1st and second etc on either side of it.

Lets say D is the perpendicular distance from the slits to the screen - as it is in your diagram.
If D>>d, the path difference between the zeroth maximum and the nth maximum is ##D_n-D=d\sin\theta_n##
You've seen a formula like that before.
 
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