Drawback of Hartree Product in Chemistry

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what is the drawback of Hartree product?
 
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I don't understand the question... could you elaborate ?
 
hmm... maybe he means: "Why is it not correct to use a simple product of occupied orbitals as the many-electron wavefunction trial ground state when calculating the energy expectation value?"

In that case, one might say that the hartree product does not satisfy the Pauli exclusion principle and so that makes it "bad". A better choice might be a slater determinent of orbitals rather than just a product. This does indeed lead to "corrections" to the ground state energy eigenvalue known as "exchange terms".
 
Not an expert in QM. AFAIK, Schrödinger's equation is quite different from the classical wave equation. The former is an equation for the dynamics of the state of a (quantum?) system, the latter is an equation for the dynamics of a (classical) degree of freedom. As a matter of fact, Schrödinger's equation is first order in time derivatives, while the classical wave equation is second order. But, AFAIK, Schrödinger's equation is a wave equation; only its interpretation makes it non-classical...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
Is it possible, and fruitful, to use certain conceptual and technical tools from effective field theory (coarse-graining/integrating-out, power-counting, matching, RG) to think about the relationship between the fundamental (quantum) and the emergent (classical), both to account for the quasi-autonomy of the classical level and to quantify residual quantum corrections? By “emergent,” I mean the following: after integrating out fast/irrelevant quantum degrees of freedom (high-energy modes...

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