E. Potential Energy: Uniformly Charged Hollow Sphere and Point Charge

In summary, the potential energy of a system involving a uniformly charged hollow sphere and a point charge can be analyzed through the principles of electrostatics. A uniformly charged hollow sphere creates a spherically symmetric electric field outside its surface, while inside, the electric field is zero. When a point charge is placed outside the sphere, the potential energy is influenced by the distance from the charge to the center of the sphere. The total potential energy is determined by the interactions between the point charge and the electric field generated by the hollow sphere, highlighting the concepts of electric potential and the conservation of energy in electrostatic systems.
  • #1
Heisenberg7
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I was doing a problem with this one detail. It says that the electric potential energy of an uniformly charged hollow sphere and a point charge is (at the surface of the hollow sphere; both positive): $$U = k \frac{q_1 q_2}{r}$$ I guess this assumes that the hollow sphere is a point charge. Now my question is, does the electric potential energy depend on other physical properties of an object? Or is this like the Newton's Shell Theorem? What if the object wasn't spherical?
 
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  • #2
Heisenberg7 said:
I guess this assumes that the hollow sphere is a point charge.
You do not tell us what are q_1,q_2 and r so that we can follow your guess condifently.
BTW
[tex]U=k \sum_{i<j}\frac{q_iq_j}{r_{ij}}[/tex]
is a fundamental rule for system of point charges whatever distributions they have.
 
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  • #3
anuttarasammyak said:
You do not tell us what are q_1,q_2 and r so that we can follow your guess condifently.
Charge of the sphere and the point charge respectively. ##r## is the radius of the sphere. Now, in general, does it hold if ##R > r## (where ##R## represents the distance from the center)?
 
  • #4
By the shell theorem, the field outside any spherically symmetric charge distribution is the same as that of a point charge with the same total charge at the center of the sphere. Yes, this is only true for spherically symmetric distributions.
 
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  • #5
Heisenberg7 said:
Now, in general, does it hold if R>r (where R represents the distance from the center)?
[tex]U(R)=k\frac{q_1q_2}{R} [/tex] for R > r
[tex]U(R)=k\frac{q_1q_2}{r} [/tex] for R < r
 
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