- #1
Cerenkov
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[Moderator's note: Spin off from previous thread due to topic change.]
It's my understanding that Edwin Hubble used the Hooker telescope to measure the red shift of galaxies only within the Local Group of galaxies to determine that the universe was expanding.
As we see here... https://en.wikipedia.org/wiki/Local_Group
...the diameter of the Local Group is given as 3 megaparsecs. Some 97 megaparsecs short of the recession value cited by Ibix. Taking into account what Ibix said about random motion and given that the Hooker could only be used to make measurements within the Local Group, surely Hubble should not have detected an overall, universal expansion?
His measurements should have only detected the presence of random motion within the Local Group?
Even if my assumption (and that is all it is) that the Hooker could not be used to measure red shifts beyond the Local Group is incorrect, does that mean that Hubble measured the recessional movements of galaxies over 100 megaparsecs distant with that telescope?
Thanks for any help given to clear up my confusion.
Cerenkov.
It's my understanding that Edwin Hubble used the Hooker telescope to measure the red shift of galaxies only within the Local Group of galaxies to determine that the universe was expanding.
As we see here... https://en.wikipedia.org/wiki/Local_Group
...the diameter of the Local Group is given as 3 megaparsecs. Some 97 megaparsecs short of the recession value cited by Ibix. Taking into account what Ibix said about random motion and given that the Hooker could only be used to make measurements within the Local Group, surely Hubble should not have detected an overall, universal expansion?
His measurements should have only detected the presence of random motion within the Local Group?
Even if my assumption (and that is all it is) that the Hooker could not be used to measure red shifts beyond the Local Group is incorrect, does that mean that Hubble measured the recessional movements of galaxies over 100 megaparsecs distant with that telescope?
Thanks for any help given to clear up my confusion.
Cerenkov.