Eigenfunction of \frac{d^2}{dx}-x^2: e^{-0.5x^2} with eigenvalue x^2-1

In summary, An eigenfunction is a special type of function that, when operated on by a linear operator, results in a scalar multiple of itself. The eigenvalue in this equation represents the constant factor by which the eigenfunction is scaled when operated on by the linear operator. The eigenvalue for this particular problem is determined by solving the differential equation, \frac{d^2}{dx}-x^2: e^{-0.5x^2} = \lambda e^{-0.5x^2}. The given function is considered an eigenfunction because when operated on by the linear operator, \frac{d^2}{dx}-x^2, it results in a scalar multiple of itself, specifically \lambda e^{-0.
  • #1
Poirot1
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show that \(\displaystyle e^{-0.5x^2}\) is an eigenfunction of the operator \(\displaystyle \frac{d^2}{dx}-x^2\) and finds it's eigenvalue. I get \(\displaystyle e^{-0.5x^2}(x^2-1)-x^2\) so it doesn't seem like its an eigenfunction.
 
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  • #2
Re: eigenfunction

The operator is defined as follows.

\[
\left(\frac{d^2}{dx^2}-x^2\right)f(x)=\frac{d^2f(x)}{dx^2}-x^2f(x).
\]
 

FAQ: Eigenfunction of \frac{d^2}{dx}-x^2: e^{-0.5x^2} with eigenvalue x^2-1

What is an eigenfunction?

An eigenfunction is a special type of function that, when operated on by a linear operator, results in a scalar multiple of itself. In other words, the function is only changed by a constant factor when operated on by the linear operator.

What is the meaning of the eigenvalue in this equation?

The eigenvalue in this equation represents the constant factor by which the eigenfunction is scaled when operated on by the linear operator. In this case, the eigenvalue is x^2-1.

How is the eigenvalue determined for this particular problem?

The eigenvalue for this particular problem is determined by solving the differential equation, \frac{d^2}{dx}-x^2: e^{-0.5x^2} = \lambda e^{-0.5x^2}. This results in the characteristic equation \lambda = x^2-1.

Why is the given function, e^{-0.5x^2}, considered an eigenfunction?

The given function is considered an eigenfunction because when operated on by the linear operator, \frac{d^2}{dx}-x^2, it results in a scalar multiple of itself, specifically \lambda e^{-0.5x^2} where \lambda = x^2-1. This satisfies the definition of an eigenfunction.

What is the significance of the term e^{-0.5x^2} in this equation?

The term e^{-0.5x^2} is significant because it is the eigenfunction of the linear operator \frac{d^2}{dx}-x^2 with eigenvalue x^2-1. This means that it is a solution to the differential equation and can be used to represent the behavior of the system described by the equation.

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