Eigenvalues and ground state eigenfunction of a weird Hamiltonian

Thunder_Jet
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Hello again everyone!

I would like to ask a question regarding this Hamiltonian that I encountered. The form is H = Aa^+a + B(a^+ + a). Then there is this question asking for the eigenvalues and ground state wavefunction in the coordinate basis. The only given conditions are, the commutator of a^+ and a is [a^+,a] = 1, and that A > 0 and B are c-number constants. I actually do not understand the meaning of c-number constants. Can anyone suggest how to attack this problem?
 
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Are you sure? The canonical convention is that \hat{a} is the destruction and \hat{a}^{\dagger} the creation operator for phonons. Then the commutator should read [\hat{a},\hat{a}^{\dagger}]=1. What you have here, is simply a "shifted harmonic oscillator". This problem you find solved in many textbooks on quantum mechanics.
 
vanhees71 said:
Are you sure? The canonical convention is that \hat{a} is the destruction and \hat{a}^{\dagger} the creation operator for phonons. Then the commutator should read [\hat{a},\hat{a}^{\dagger}]=1. What you have here, is simply a "shifted harmonic oscillator". This problem you find solved in many textbooks on quantum mechanics.

Ok, so a and a^+ are the annihilation and creation operators in the harmonic oscillator problem. I thought there are other operators. Thanks for your comment! Anyway, in this shifted harmonic oscillator case, do you expect that the solution for example, the eigenvalues are just shifted by a constant? I think the same is true for the wavefunction.
 
May I know how can I obtain the eigenvalues using the usual eigenvalue problem here? I am quite confused here now.
 
Define new creation and annihilation operators
\tilde a = a+c
\tilde a^\dagger = a^\dagger + c
where c is a real constant. Choose c so that the hamiltonian is
H=A \tilde a^\dagger \tilde a + d
where d is another constant. Note that
[\tilde a, \tilde a^\dagger]=1
 
Avodyne said:
Define new creation and annihilation operators
\tilde a = a+c
\tilde a^\dagger = a^\dagger + c
where c is a real constant. Choose c so that the hamiltonian is
H=A \tilde a^\dagger \tilde a + d
where d is another constant. Note that
[\tilde a, \tilde a^\dagger]=1

Hmmm, sounds ok. Thank you for your suggestion. But I am really new to ladder operators, how would you use this translated a+ and a?
 
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