Elastic Collisions: What Went Wrong in My Calculation?

AI Thread Summary
The discussion revolves around a calculation error in an elastic collision problem involving two objects with different masses and velocities. The user is confused by obtaining two sets of answers that both seem valid when checked against the original equations. They express uncertainty about whether one of the objects should be moving in a negative direction post-collision, indicating a potential misunderstanding of elastic collision principles. A suggestion is made to combine the conservation of momentum and kinetic energy equations into a single linear equation to simplify the problem. The user is encouraged to review their notes for this alternative approach to avoid the quadratic complications.
fuzzish
Messages
5
Reaction score
0
Just to begin, uhh. I'm 75% sure my work makes logical sense [I hope], and that my problem lies in a computational error. But I really don't know why my answers aren't working out. I've now gone through the problem in 3 different ways, and I keep getting the same answer, but it's apparently still incorrect. If it is an arithmetic error, sorry for making you read through all of this to fix such a stupid mistake >.>

Homework Statement



A 12.7g object moving to the right at 26.5cm/s overtakes and collides elastically with a 10.5g object moving in the same direction at 10.7cm/s.

Find the velocity of the faster object after the collision. Answer in units of cm/s.

Find the velocity of the slower object after the collision. Answer in units of cm/s.

Homework Equations



m1v1 + m2v2 = m1v3 + m2v4

.5m1v1^2 + .5m2v2^2 = .5m1v3^2 + .5m2v4^2

And, sorry in advanced for the ugly way that equation appears. And for the work that is likely to look just as messy.

The Attempt at a Solution



m1 = 12.7g ; v1 = 26.5cm/s
m2 = 10.5g ; v2 = 10.7cm/s

I plugged those two into the first equation and got:
448.9 = 12.7v3 + 10.5v4

Rearranged for v3:
v3 = 35.35 - 0.827v4

I then plugged in the m1, v1, m2, and v2 into the second equation and got:
5060.36 = 6.35v3^2 + 5.25v4^2

Plugged in the v3 from the previous equation:
5060.36 = 6.35 ( 35.35 - 0.827x )^2 + 5.25 x^2

AND HEREEEE I FIND MY PROBLEMO.
My TI-89 keeps giving me two answers:
v3 = 28 [in which case v4 = 8.89]
or
v3 = 10.7 [and thus v4 = 29.8]

Problemo Uno: Why are there two answers? O_o? And both seem to work when plugged back into the original equations? This point makes me most uncomfy and confused.

Problemo Dos: If it's an elastic collision, shouldn't one of the objects be moving in a negative direction now? Perhaps my thought process is wrong here though, but idk.

/////////////////////
Thanks in advanced to whoever offers help yay. And I know I'm a noob leeching off these forums, so just so I don't feel like I'm nomming up the answer and running away, I'll stay around to help someone else if I can xD.
 
Physics news on Phys.org
Your set-up is correct, but neither of your solutions work when I plug them in here.
 
Auurrghhghghghhhh. Fifth round of calculator plug and chug, and I still got 2 answers, but the one that worked worse out of the two turned out to be the right pair. This. Is. Really. Weird. Maybe I need a new calculator, idk.

Anyways, thanks for rechecking my set-up :].
 
By the way, for one-dimensional elastic collisions, you can combine the two equations to come up with a third one that relates the objects' relative velocities. It's linear so you can avoid the quadratic messiness. Check your notes or your book for its derivation.
 
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top