Electric Field Above Square: Find E-Field at z Height

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AI Thread Summary
The discussion focuses on calculating the electric field at a height z above a square with uniform surface charge density σ. The integral used for the electric field is E = (zσ / 4πε₀) ∫∫ (dx dy) / (x² + y² + z²)^(3/2), but the user suspects it may yield an incorrect result. They seek clarification on whether there is an error in the integral setup. Participants are encouraged to review the integral formulation for potential mistakes. The conversation emphasizes the importance of correctly applying integral calculus in electrostatics.
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Homework Statement


Find the electric field a height z above a square of side length a with uniform surface charge \sigma

Homework Equations


The Attempt at a Solution


E=\frac{z\sigma}{4\pi\epsilon_0}\int^{a/2}_{-a/2}\int^{a/2}_{-a/2}\frac{dx dy}{(x^2+y^2+z^2)^{3/2}}
(in the z direction). However, unless I maple'd wrong, this gives the wrong answer. Can you anyone see a problem with the way the integral is set up?
 
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Looks right to me.
 
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