Electric Potential-finding unknown distance

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A 1.5 x 10^-9 C positive charge is located at the origin, while a -1.5 x 10^-9 C charge is positioned 4.5 m to the right, creating an electric potential of -1.8 V at a distance d from the negative charge. The equation for electric potential, V = k [sum] (q/r), is applied to find d, but the initial setup contained an algebraic error. The corrected equation is -1.8 V = k [1.5 x 10^-9 / (4.5 + d) + (-1.5 x 10^-9 / d)]. The discussion focuses on resolving the algebra to find the correct value of d. The thread emphasizes the importance of accurate equation setup in solving electric potential problems.
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Homework Statement



A 1.5 10-9 C charge is at the origin, and a -1.50 10-9 C charge is 4.5 m to the right on the positive x-axis. The electric potential is -1.8 V at a point on the x-axis that is a distance d to the right of the negative charge. Find d.

Homework Equations



V = k [sum] (q/r)

The Attempt at a Solution



-1.8V = k [(1.5 x 10-9 / 4.5 + x ) + (-1.5 x 10-9 / x )]

Maybe I'm doing the algebra incorrectly, but I continue to get the wrong answer although I think the set-up is correct.
 
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abspeers said:

The Attempt at a Solution



-1.8V = k [(1.5 x 10-9 / 4.5 + x ) + (-1.5 x 10-9 / x )]

Maybe I'm doing the algebra incorrectly, but I continue to get the wrong answer although I think the set-up is correct.

The equation is incorrect, it should be

-1.8V = k [1.5 x 10-9 / (4.5 + x ) + (-1.5 x 10-9 / x )]

Show how do you get x.

ehild
 
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