Electric Potential of Uniformly Charged Sphere

Click For Summary
The discussion focuses on calculating the electric potential at specific points within and on the surface of a uniformly charged nonconductive sphere. The sphere has a radius of 2.31 cm and a charge of 3.5 fC, with the potential at its center set to zero. The user attempts to apply Gauss' Law and the relationship between electric field and potential but encounters discrepancies in their calculations. They are advised to clarify their equations and show their work more explicitly to identify the source of their error. The conversation emphasizes the importance of correctly applying formulas in electrostatics.
ktbobabee@aol
Messages
1
Reaction score
0

Homework Statement


A nonconductive sphere has radius R=2.31 cm and uniformly distributed charge q==3.5 fC. Take the electric potential at the sphere's center to be V=0. What is V at the radical distance r=1.45cm and at r=2.31 cm


Homework Equations


Gauss' Law
V=E*ds


The Attempt at a Solution


E=kqr/R^3
then V=E*ds
I keep getting an answer that is 20 times smaller then the actual.


 
Physics news on Phys.org
Your second equation "V=E*ds" is not correct. The RHS is a differential element, while the LHS is not. Besides, what is "s"?

Please show your work more explicitly. With what you've shown so far, there is no way one can tell you exactly where your error is.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
601
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
12
Views
2K
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
11
Views
2K