Is MgCl2 and NaOH Reaction Endothermic or Exothermic?

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The discussion centers on the reaction between MgCl2 and NaOH, questioning whether it is endothermic or exothermic. The experiment involved adding MgCl2 and NaOH, resulting in a color change from white to pink upon heating and cooling. The participant initially believed the reaction was endothermic due to the shift towards reactants when heated. However, the explanation provided clarified that an exothermic reaction would shift left with added heat, supporting the conclusion that the reaction is indeed exothermic. The discussion concludes with the participant acknowledging the clarity gained from the explanation.
kuahji
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I have the equation Mg(OH)2 (s) -> Mg2+ (aq) + 2 OH- (aq)

I started out with 20 drops of 1.0M MgCl2 in a well & 10 drops of .5M NaOH. Phenolphthalein was also added. When I heated the mixture, it became white, when it cooled it became pink. So, how can I tell if it was endo or exothermic? I want to say it was endothermic because it shifted to the reactant side when heated, but I'm not sure, almost doesn't seem right if you look at the original equation.
 
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It might be helpful to consider energy like a component in the reaction. Let me explain.

An exothermic reaction releases energy to its surroundings. Usually we write this as:

(reactants) <=> (products) delta-H < 0

However, it's often useful to think of it like this:

(reactants) <=> (products) + (energy)

So by Le Chatelier's principle, if you add energy (by heating) to an exothermic reaction, you should shift the equilibrium to the left, i.e. towards the reactant's side. Vice versa for an endothermic reaction, which shifts to the right, i.e., towards the product's side.

Do you now see the answer to your original question?
 
Yes I do, thank for the explanation.
 

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