Escape Speed from Earth for 7500kg Spacecraft

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    Escape Speed
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The escape speed from Earth for a spacecraft is calculated using the formula square root of 2GM/R, where G is the gravitational constant and R is the radius of Earth. A user calculated the escape speed to be 3.4 x 10 m/s but was informed that this value is incorrect. The radius of Earth used in the calculation was confirmed as 6.371 x 10^6 m, and the mass of Earth as 5.9742 x 10^24 kg. The discussion emphasizes the importance of using accurate values for G and the correct radius in calculations. Accurate calculations are crucial for determining the correct escape speed.
kubombelar
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what is the escape speed from Earth for a 7500kg spacecraft ?
radius of Earth is 6.38*10m and mass is 5.98*10kg.

Homework Equations


square root of 2GM/R

3. The Attempt at a Solution . I found escape speed to be 3.4*10ms. Is this right?
 
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The radius of the Earth is 6.371x106 m.
The mass of the Earth is 5.9742x1024 Kg.

Your answer is not correct.
 
jimmy those were the given values in my test. And am still finding the same answers with yo values
 
kubombelar said:
I found escape speed to be 3.4*10ms.
Show the details of your calculation. (Including the exponents!)
 
What value are you using for G?

G is approximately 6.673x10-11 m3/kg*s2
 
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