Evaluate QM Potential Well Proposal for Low-n Transitions

AI Thread Summary
The proposal to construct an infinite potential well for studying low-n transitions in electrons raises several concerns. Key questions include whether electrons can transition without a nucleus and the nature of low-n transitions themselves. The calculations suggest that the emitted wavelengths may fall outside the visible spectrum, which could limit the experimental feasibility. The discussion indicates a general recommendation against the proposal, primarily due to uncertainties regarding the physics involved and the practicality of the measurements. Overall, the proposal lacks clarity on fundamental concepts and experimental outcomes.
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Homework Statement



An experimental physicist submits a proposal to a granting agency requesting support to construct an infinite potential well analogous to the one shown in Figure 3.5 (an electron trapped in a one dimensional box made of electrodes and grids in an evacuated tube). Specifically, the proposal is to build a well with L = 1mm, inject some electrons into it, and then measure the wavelength of photons emitted during low-n transitions via optical spectroscopy. As an expert on quantum mechanics, you are asked to evaluate the proposal. What is your recommendation?

Homework Equations



E = \frac{\pi^2\hbar^2}{2 m L^2}n^2

\lambda = \frac{h c }{E}


The Attempt at a Solution



Questions: Can electrons transition without a nucleus? Is it responding to some nucleus outside of the well? Does it have nothing to do with nuclei at all? What exactly are low-n transitions?

I'm very confused, so any direction would be appreciated. I know that the proposal should be refused, but I don't know why. By playing around with the equations above, I though perhaps that the wavelength wasn't in the visual spectrum, but I'm not sure that combining the two equations even makes sense.
 
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you can take "low-n transitions" to mean n=1 or 2 or so. That is, plug in n=1 or 2 or whatever to the 'E' formula and find E. Then plug that E into the '\lambda formula and find \lambda. Compare the wavelength you find to the wavelength of visible light.
 
Thank you very much. That's what I did initially, but I wasn't sure if that was the right method.
 
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