Evolution of temperature (adiabatic procsses)

AI Thread Summary
In adiabatic processes, the heat transfer (dQ) is zero, leading to a simplification where the change in entropy (ds) is also zero, which aids in deriving the differential equation. The discussion highlights the importance of understanding the physical implications of this simplification, particularly that it indicates a reversible process. The original poster seeks clarification on eliminating the energy term (dU) from their solution. The conversation emphasizes the relationship between thermodynamic principles and the derivation of equations in adiabatic conditions. Understanding these concepts is crucial for accurately applying them in thermodynamic problems.
ted1986
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Hello,

I'm trying to derive a differential equation as requested in the attached exercise (thermal1.jpg).
I'm not quite sure my solution is the right answer (my_solution1.jpg).
How do I get rid of the energy dU ?

Thnks


Ted
 

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well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation
 
sgd37 said:
well in an adiabatic processes dQ = 0 so ds = 0 giving you quite a simple derivation of the differential equation


OK, It sure gives a simple derivation of the differential equation, but what is the physical explanation for that?

Thanks
 
it most generally means that it is a reversible process
 
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