Example of Xn + Yn Limit | Help with Problem

In summary, the conversation discusses the concept of convergence and divergence of sequences, particularly the theorem that states the sum of two convergent sequences is convergent. It also raises the question of whether two defined sequences, Xn and Yn, and the constant gamma are equal to one. An example is given with Xn and Yn defined as the sum from 1 to infinity of 1 and -1^kx^k, respectively, to illustrate the concept.
  • #1
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Give an example of two sequences Xn(sum from 1 to infinity) and Yn(sum from 1 to infinity) where lim (as n tends to infinity) of (Xn + Yn ) exists but lim (as n goes to infinity) of(Xn +Yn) does not equal lim (as n goes to infinity) Xn + lim(as n goes to infinity) Yn.
 
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  • #2
By the old theorem:

[tex]\sum_n (x_n+y_n)=\sum_n x_n + \sum_n y_n[/tex]
if [itex] \sum x_n[/itex] and [itex]\sum_y_n[/itex] are convergent series, your only hope is to have either [itex] \sum x_n[/itex] or [itex] \sum y_n[/itex] divergent.

Maybe also allowed: Even if [itex]\sum (x_n+y_n)=\sum x_n + \sum y_n[/tex], the radii of converge need not be the same.
 
  • #3
Does the two sequence Xn and Yn defined??

If not (this is a wild guess), is gamma constant one? Because:

[tex]\sum_{n=1}^\infty\frac{1}{n}[/tex]
is undefined, and also

[tex]-\sum_{n=1}^\infty\frac{(-1)^nx^n}{n}[/tex]
is also undefined

but [tex]\sum_{n=1}^\infty\frac{1}{n} - \sum_{n=1}^\infty\frac{(-1)^nx^n}{n}[/tex]=\gamma=0.577...
 
  • #4
Does the two sequence Xn and Yn defined??

If not (this is a wild guess), is gamma constant one? Because:

[tex]\sum_{n=1}^\infty\frac{1}{n}[/tex]
is undefined, and also

[tex]-\sum_{n=1}^\infty\frac{(-1)^nx^n}{n}[/tex]
is also undefined

but [tex]\sum_{n=1}^\infty\frac{1}{n} - \sum_{n=1}^\infty\frac{(-1)^nx^n}{n}=\gamma=0.577...[/tex]
 
  • #5
[tex]X_n=\sum_{k=1}^n 1[/tex]
[tex]Y_n=\sum_{k=1}^n -1[/tex]
 

FAQ: Example of Xn + Yn Limit | Help with Problem

What is an example of Xn + Yn limit?

An example of Xn + Yn limit is when we have the sequence xn = 1/n and yn = 1/n. The limit of Xn + Yn as n approaches infinity is 0. This can be represented as lim(n→∞) (1/n + 1/n) = lim(n→∞) (2/n) = 0.

How do I solve a limit problem involving Xn + Yn?

To solve a limit problem involving Xn + Yn, you can follow these steps:

  • 1. Identify the sequence xn and yn
  • 2. Write the limit expression as lim(n→∞) (xn + yn)
  • 3. Simplify the expression using basic algebra
  • 4. If the limit still contains infinity or indeterminate forms (such as 0/0 or ∞/∞), use L'Hôpital's rule to find the limit
  • 5. If the limit is still indeterminate, try using other limit theorems or techniques to solve it

What is the difference between a limit involving Xn + Yn and a limit involving Xn * Yn?

The difference between a limit involving Xn + Yn and a limit involving Xn * Yn is the operation being performed. In Xn + Yn, the two sequences are added together, whereas in Xn * Yn, they are multiplied together. This can result in different limit values and require different solving techniques.

Can I use the squeeze theorem to solve a limit involving Xn + Yn?

Yes, the squeeze theorem can be used to solve a limit involving Xn + Yn. The squeeze theorem states that if two sequences, Xn and Yn, have the same limit as n approaches infinity and a third sequence, Zn, is always between Xn and Yn, then Zn also has the same limit. This can be helpful when solving limits involving Xn + Yn, as it allows us to find a tighter bound on the limit value.

Is there a general formula for solving limits involving Xn + Yn?

There is no general formula for solving limits involving Xn + Yn. The method for solving these types of limits may vary depending on the specific sequence and operation involved. However, there are some common techniques and theorems, such as L'Hôpital's rule and the squeeze theorem, that can be used to solve a variety of limit problems involving Xn + Yn.

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