Exploring E-e Repulsion: Stability of Half and Full P Sub-Shells Explained

[htneT]

I am fully aware that a half filled p sub-shell is stable due to no repulsion as electrons first occupy the orbitals singly before pairing up according to Hunds rule, why is that however a fully occupied p sub-shell with 6 electrons is also considered stable? Where as a filled s sub-shell with 2 electrons is said to undergo e-e repulsion, hence the I.E value of He is less than that of Hydrogen's I.E by a factor of 2 (90% to be exact).

In short: Why is a full p sub-shell with 6 electrons not said to undergo e-e repulsion (considered stable), whereas a full s sub-shell with 2 electrons is said to undergo e-e repulsion (unstable).

 

[Vagn]

The ionization energy of Helium is a little less than twice that of atomic hydrogen, i.e. helium is more inert than atomic hydrogen.
See the table of values here.

 

[htneT]

Doesn't it have to do with e-e repulsion?

 

[Vagn]

Doesn't it have to do with e-e repulsion?

Does what have to do with electron-electron repulsion? You said that helium has a lower ionization energy than helium, which is not the case. Similarly you are talking about p sub-shells but only referring to hydrogen and helium, which only have half and fully filled 1s sub-shells respectively.

 

[htneT]

Does what have to do with electron-electron repulsion? You said that helium has a lower ionization energy than helium, which is not the case. Similarly you are talking about p sub-shells but only referring to hydrogen and helium, which only have half and fully filled 1s sub-shells respectively.

My main question is why is a full p sub-shell considered stable, whereas a full s sub-shell considered unstable and its electrons undergo e-e repulsion?

 

[blue_leaf77]

Where as a filled s sub-shell with 2 electrons is said to undergo e-e repulsion

Each electron in a multi-electron atom will of course experience e-e repulsion regardless of which subshell the electron under consideration occupies.

a full s sub-shell considered unstable

What is the measure of stability/instability you are using, I.E.? Ionization energy is not only determined by the number of electrons present in the atom, but also by the nuclear charge.