Exploring Real and Complex Roots of x^n-a=0

In summary, in math class today, we learned that the equation x^n-a=0 has n roots. However, when considering real and complex roots, we wondered if it was possible to have n real roots for n>2. After some exploration, we discovered that the only way for there to be n real roots is if a=0, and even then, there will be 2 real roots when n is even and 1 real root when n is odd.
  • #1
msmith12
41
0
In math class today, we were discussing quadratic residues, and one of the things that came up was the fact that

[tex]
x^n-a=0
[/tex]

has n roots.

This just made me start thinking about real and complex roots. A question that I had was whether, given n>2, is it possible to have n real roots in the above eqn? If not, is there a simple proof to show why it is not possible?
 
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  • #2
Take a = 0. One might count that as a trivial special case though...
 
  • #4
msmith12 said:
In math class today, we were discussing quadratic residues, and one of the things that came up was the fact that

[tex]
x^n-a=0
[/tex]

has n roots.

This just made me start thinking about real and complex roots. A question that I had was whether, given n>2, is it possible to have n real roots in the above eqn? If not, is there a simple proof to show why it is not possible?

Well, for
[tex]x^n=a[/tex]
and
[tex]a>0[/tex]
The roots will be of the form:
[tex]\sqrt[n]{a} (\cos{\frac{k2\pi}{n} + i \sin\frac{k2\pi}{n}})[/tex]
with [itex]k[/itex] ranging from [itex]1[/itex] to [itex]n[/itex].
(You can check this for yourself by, for example, multiplying, if you like).
Now, it's easy to see that this is real only if:
[tex]\sqrt[n]{a}=0[/tex]
or
[tex]sin\frac{2k\pi}{n}=0 \Rightarrow \frac{k}{n} \in \{1,\frac{1}{2}\}[/tex]
(There are other values, but they aren't possible for our range of k.)

From there it's easy to see that for non-zero [itex]a[/itex] if [itex]n[/itex] is even, there will be 2 real roots, and when [itex]n[/itex] is odd, there will be one.
 

FAQ: Exploring Real and Complex Roots of x^n-a=0

What is the purpose of exploring real and complex roots of x^n-a=0?

The purpose of exploring real and complex roots of x^n-a=0 is to find the solutions or values of x that make the equation true. This allows us to solve for the unknown variable and understand the behavior of the function.

How are real and complex roots different?

Real roots are values of x that make the equation true when plugged in, while complex roots have an imaginary component and cannot be expressed as a real number. Complex roots come in pairs, such as a+bi and a-bi, where a and b are real numbers and i is the imaginary unit.

How do I find the real and complex roots of x^n-a=0?

To find the roots, you can use the quadratic formula for n=2, or use a graphing calculator or software to solve for larger values of n. For complex roots, you can use the complex conjugate theorem to find the other root in the pair.

What does the value of n represent in the equation x^n-a=0?

The value of n represents the degree of the polynomial, which is the highest exponent of x in the equation. This determines the number of roots the equation will have, with a maximum of n roots.

How are real and complex roots related to the graph of x^n-a=0?

The real roots correspond to the x-intercepts of the graph, where the function crosses the x-axis. Complex roots do not have a visual representation on the graph, but they still affect the behavior of the function and its shape.

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