Exponential growth of populations (Q=Ae^kt)

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The discussion revolves around solving the exponential growth equation for a rabbit population, given by N=80e^(0.02t), to determine how many days it will take for the population to reach 500 rabbits. The initial attempts to manipulate the equation led to confusion, particularly with variable usage and algebraic steps. Participants emphasized the importance of correctly isolating the exponent by dividing both sides by 80 and then applying the natural logarithm. Ultimately, the correct approach simplifies to ln(6.25) = 0.02t, leading to the conclusion that it takes approximately 92 days for the population to reach 500 rabbits. The conversation highlights the necessity of clear algebraic manipulation in solving exponential equations.
Alistair
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Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=kt
Then divided both sudes by x to give:

A ln Q = t
k


Which after substitution looked like this:

80 ln 500 = t
0.02

Which gave t=24,858 days.
where as the answer is 92 days...
 
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Alistair said:

Homework Statement


The number of rabbits in a colony is given by N=80e^(0.02t) where t is in days.
c) After how many days will there be 500 rabbits?

N=500
A=80
k=0.02
t=?

Homework Equations


(ln being the exponential logarithm)
Q=Ae^kt
and possibly the conversion formula: ln y = x --> y=e^x

The Attempt at a Solution



what i tried was coverting Q=Ae^kt to A ln Q=xt
Then divided both sudes by x to give:

A ln Q = t
x
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.
 
marcusl said:
This equation is wrong. Perhaps you are getting confused with your variables; there's no reason to introduce x, stick with A, k and t and try again.

Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
 
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.
 
danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...
 
Alistair said:
Yeah i ment k not x.
in my maths book in the examples it has x. but it still doesn't work with k in there... :frown:
If you really believe that using the letter "x" gives you a different equation that using the letter "k", you need to review basic algebra!

danago said:
Start by dividing both sides by 80, so you isolate the exponent part. From there it might seem easier.

Alistair said:
i don't know how dividing both sides by 80 will make it easier or alter the answer in any way...
i want to know if there is a problem with my working. I am not sure if it is even the right formula...

You have already been told that there is a problem with your "working"!

You are given the formula N= 80e^{0.02t} so of course, that the correct formula. You are also told that N= 500 so the equation you want to solve is 80 e^{0.02t}= 500. Surely, it would be an obvious first step to divide both sides by 80? After you have done that take the natural logarithm of both sides.
 
ok got it.
500 = 80e^0.02t
goes to
ln 6.25 = t
0.02
 
Okay, now, what is your answer to the question?
 

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