F = ma 2007 Exam - Question #25 - SHM with a box in water

AI Thread Summary
The discussion focuses on calculating the period of small oscillations for a water pogo, a box-shaped object bobbing in water. The buoyant force is identified as the restoring force, and participants explore methods to derive the period from this force. One approach involves equating gravitational potential energy with the work done by buoyancy, while another suggests using the sum of forces to set up a differential equation. The conversation highlights that understanding the physics is crucial, as the exam question is designed to test both conceptual knowledge and mathematical skills. Ultimately, the goal is to recognize that the problem parallels the behavior of a mass on a spring in simple harmonic motion.
physicsod
Messages
9
Reaction score
0

Homework Statement



Find the period of small oscillations of a water pogo, which is a stick of mass m in the shape of a box (a rectangular parallelepiped.) The stick has a length L, a width w and a height h and is bobbing up and down in water of density ρ. Assume that the water pogo is oriented such that the length L and width w are horizontal at all times. Hint: The buoyant force on an object is given by Fbuoy = ρVg where V is the volume of the medium displaced by the object and ρ is the density of the medium. Assume that at equilibrium, the pogo is floating.


Homework Equations


Fbuoy = ρVg.
Fg = mg


The Attempt at a Solution


So I created the general box (or "parallelepiped") and set it's dimensions as L, w, and h. I let the height underneath the water be "a," where a is some fraction of h. Then, the buoyant force is Fbuoy = ρLwag. But how do I extract the period from this equation?
 
Physics news on Phys.org
The bouyant force is the restoring force.
Your parameter "a" is the bit that has SHM.
 
Well yeah, I understood that bit. Is there a general way to go from the restoring force to a general SHM equation?

EDIT: I just thought of setting the gravitational potential energy (mga) equal to the work done by the buoyancy force, for conservation of mechanical energy. Is this correct?
 
Last edited:
Ahhh... the usual way is just to set ƩF=ma ... so it is unfortunate that you have used a as your emmersion parameter.

If h0 = the equilibrium level, then set y = displacement from equilibrium downwards, thus: \vec{F}_{bouy}+\vec{F}_{grav}=m\ddot{\vec{y}}, resolve the forces in terms of m and y, and solve the differential equation.
Approximate for small a small initial downwards displacement y0 ... which will become the amplitude of the oscillations.
 
Yuck, so this is a basic diff eq question? Darn, well I guess that's expected for question 25 on the exam. I'll try that out, thanks. :)
 
Yeah - though it has a standard solution - like the mass on a spring: buoyancy standing in for the spring force. So, if you understand the physics you can just do it by substitution.

They don't really expect you will solve the DE in an exam - that's just to slow you down if you didn't understand the material. Too little understanding and you won't be able to complete the exam. Sneaky see - ideally they want you to understand what you are doing but if you are really fast at the math, well, that's good too. Most people do a bit of both.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...

Similar threads

Replies
9
Views
8K
Replies
9
Views
3K
Replies
13
Views
3K
Replies
11
Views
3K
Replies
8
Views
5K
Replies
13
Views
2K
Back
Top