Fermi Distribution of Energy Levels

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The discussion focuses on calculating the energy difference between two electron energy levels using the Fermi-Dirac distribution. The occupation probabilities for the levels are given as ¼ and ¾. The formula used is P(E) = 1/(e^(E/kBT) - 1), leading to the calculations E1 = kBT ln(5) and E2 = kBT ln(7/4). The resulting energy difference is expressed as ΔE = E1 - E2 = kBT ln(20/7) = 1.0498 kBT. There is a concern regarding the inclusion of the chemical potential in the calculations.
lvuongt
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Based on Fermi distribution, if there are two electron energy levels with occupation possibility of ¼ and ¾, respectively, calculate energy difference between these two levels.
 
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lvuongt said:
Based on Fermi distribution, if there are two electron energy levels with occupation possibility of ¼ and ¾, respectively, calculate energy difference between these two levels.
Hello, Did you tried an attempt for obtaining a solution? I advice you to start from Fermi-Dirac distribution formula! Write down the formula and each terms present in the formula, then you knwo what to do next,
Cheers, Rajini
 
Sorry forgot to put my attempt,

P(E)=1eE/kBT−1 ------------(1) from eq. 1, P(E1)=1/4 and P(E2)=3/4 E1=kBTln(5) E2=kBTln(7/4) hence DeltaE=E1−E2=kBTln(20/7)=1.0498 kBT

I was sure if this answer was okay since the distribution include the chemical potential as well.
 
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